Can y'all help me with number 4
2 answers:
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Answer:
The IUPAC name of compound is 6-Ethyl-2-Octene.
Explanation:
First of all draw a straight chain of 8 carbon atoms.
Make a double bond between carbon number 6 and 7 numbering from left.
Add ethyl group at position 3 starting from left.
The structure sketched is attached below,
According to rules the longest chain containing a double bond is selected. Numbering is started from the end to which double bond is nearer. So, in our case the double bond starts at carbon 2, hence parent name of compound is 2-Octene. Then the substituent at position 6 is named.
The IUPAC name of compound is 6-Ethyl-2-Octene.
Explanation:
First of all draw a straight chain of 8 carbon atoms.
Make a double bond between carbon number 6 and 7 numbering from left.
Add ethyl group at position 3 starting from left.
The structure sketched is attached below,
According to rules the longest chain containing a double bond is selected. Numbering is started from the end to which double bond is nearer. So, in our case the double bond starts at carbon 2, hence parent name of compound is 2-Octene. Then the substituent at position 6 is named.