Question

6.

Answer 1

Answer:

4Na  +   O₂  →   2Na₂O  

6.82g

Explanation:

The combustion of sodium involves combining the element with oxygen gas:

              4Na  +   O₂  →   2Na₂O  

We have been given 5g of Na.

The balanced reaction equation is given as shown above. This reaction is also a synthesis or combination reaction.

b. Maximum amount of product that can be obtained.

Sodium is the limiting reactant and it will determine the amount of product that can be formed.

  To solve this, we find the number of moles of the given sodium.

  Mass of given sodium  = 5g

    Molar mass of Na  = 23g/mol

  Number of moles of Na  = $\frac{mass}{molar mass}$  

Insert the parameters and solve;

 Number of moles of Na  = $\frac{5}{23}$    = 0.217moles

  From the balanced reaction equation:

         4 moles of Na will produce 2 moles of Na₂O  

      0.217 moles of Na will produce $\frac{0.217 x 2}{4}$   = 0.11mole of Na₂O  

So;

 Mass of Na₂O   = number of moles x molar mass

    Molar mass of Na₂O   = 2(23) + 16  = 62g/mol

 Mass of Na₂O   = 0.11 x 62  = 6.82g