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Xelga [282]
4 years ago
6

What can neutrons change into

Chemistry
1 answer:
Elan Coil [88]4 years ago
7 0
I think they can change into ions
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How many molecules of NH3 are in 45 mol of NH3 ?​
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Answer:

Explanation:

5

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3 years ago
If you burn 52.0 g of hydrogen and produce 465 g of water, how much oxygen reacted?
Nadusha1986 [10]
Well, since matter doesn't simply poof into existence and water is H2O, 465g of water is a combination of 52.0g of H and 413g O
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What is neutralization ?
blagie [28]

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"a chemical reaction in which acid and a base react quantitatively with each other"

Explanation:

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If atoms are not destroyed, what happens to them
Snowcat [4.5K]

The 1st law of thermodynamics doesn't  specify that matter can be created nor destroyed, but that the total amount of energy in a closed system cannot be created nor destroyed though it can be changed from one form to another.

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3 years ago
Suppose that 0.48 g of water at 25 ∘ C condenses on the surface of a 55- g block of aluminum that is initially at 25 ∘ C . If th
mamaluj [8]

Answer:

49^oC

Explanation:

At 25^oC, the heat of vaporization of water is given by:

\Delta H^o_{vap} = 43988 J/mol\cdot \frac{1 mol}{18.016 g} = 2441.6 J/g

The water here condenses and gives off heat given by the product between its mass and the heat of vaporization:

Q_1 = \Delta H^o_{vap} m_w

The block of aluminum absorbs heat given by the product of its specific heat capacity, mass and the change in temperature:

Q_2 = c_{Al}m_{Al}(t_f - t_i)

According to the law of energy conservation, the heat lost is equal to the heat gained:

Q_1 = Q_2 or:

\Delta H^o_{vap} m_w = c_{Al}m_{Al}(t_f - t_i)

Rearrange for the final temperature:

\Delta H^o_{vap} m_w = c_{Al}m_{Al}t_f - c_{Al}m_{Al}t_i

We obtain:

\Delta H^o_{vap} m_w + c_{Al}m_{Al}t_i = c_{Al}m_{Al}t_f

Then:

t_f = \frac{\Delta H^o_{vap} m_w + c_{Al}m_{Al}t_i}{c_{Al}m_{Al}} = \frac{2441.6 J/g\cdot 0.48 g + 0.903 \frac{J}{g^oC}\cdot 55 g\cdot 25^oC}{0.903 \frac{J}{g^oC}\cdot 55 g} = 49^oC

6 0
3 years ago
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