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Dmitrij [34]
2 years ago
9

Part A of the lab involved adding 4 mL increments of distilled water to 5.00 mL of antimony trichloride solution. The antimony t

richloride solution contains 0.10 M SbCl3 in 4.5 M HCl. Calculate the concentrations of SbCl3 and H /Cl- in the test tube after 12.0 mL of distilled water has been added. Assume dilution only.
Chemistry
1 answer:
Mrrafil [7]2 years ago
3 0

Answer:

0.0238M SbCl3, 1.07M H+, 1.14M Cl-

Explanation:

The total volume of the solution is:

4mL + 5.00mL + 12.0mL = 21mL

As the volume of the SbCl3 is 5.00mL, the dilution factor is:

21mL / 5.00mL = 4.2 times

The concentration of SbCl3 is:

0.10M SbCl3 / 4.2 times = 0.0238M SbCl3

The concentration of H+ = [HCl]:

4.5M / 4.2 times = 1.07M H+

The initial concentration of Cl- is:

3 times SbCl3 + HCl = 0.10M*3 + 4.5M =

<em>3 times SbCl3 because 1 mole of SbCl3 contains 3 moles of Cl-</em>

4.8M Cl- / 4.2 times = 1.14M Cl-

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3 years ago
A chemist pours 1 mol of zinc granules into one beaker and 1 mol of zinc chloride powder into another beaker. What do the two sa
irina1246 [14]
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2 years ago
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The most reactive metals are the ________ to corrode.
katrin [286]

Answer:

2. quickest

Explanation:

because they have lower activation energy.

3 0
3 years ago
In the hydrogenation of ethylene using a nickel catalyst, the initial concentration of ethylene is 2.00mol?L?1 and its rate cons
gavmur [86]

Answer:

The rate of reaction of a zero-order reaction  is 0.0020 mol/L.

Explanation:

The rate expression of the zero order kinetic are :

R=k[A]^o

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R = rate of reaction

We have :

Rate constant of the reaction , k = 0.0020 mol/L s

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8 0
2 years ago
3. Given the following equation:
miskamm [114]

Answer:

4.767 grams of KCl are produced from 2.50 g of K and excess Cl2

Explanation:

The balanced equation is

2 K+ Cl2 --->2 KCI

Here the limiting agent is K. Hence, the amount of KCl will be calculated as per the mass of 2.50 gram of K

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Number of moles is 2.5 grams = \frac{2.5}{39.098} = 0.064

So, 2 moles of K produces 2 moles of KCL

0.064 moles of K will produces 0.064 moles of KCl

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Mass of 0.064 moles of KCl is 4.767 grams

4 0
2 years ago
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