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Dmitrij [34]
2 years ago
9

Part A of the lab involved adding 4 mL increments of distilled water to 5.00 mL of antimony trichloride solution. The antimony t

richloride solution contains 0.10 M SbCl3 in 4.5 M HCl. Calculate the concentrations of SbCl3 and H /Cl- in the test tube after 12.0 mL of distilled water has been added. Assume dilution only.
Chemistry
1 answer:
Mrrafil [7]2 years ago
3 0

Answer:

0.0238M SbCl3, 1.07M H+, 1.14M Cl-

Explanation:

The total volume of the solution is:

4mL + 5.00mL + 12.0mL = 21mL

As the volume of the SbCl3 is 5.00mL, the dilution factor is:

21mL / 5.00mL = 4.2 times

The concentration of SbCl3 is:

0.10M SbCl3 / 4.2 times = 0.0238M SbCl3

The concentration of H+ = [HCl]:

4.5M / 4.2 times = 1.07M H+

The initial concentration of Cl- is:

3 times SbCl3 + HCl = 0.10M*3 + 4.5M =

<em>3 times SbCl3 because 1 mole of SbCl3 contains 3 moles of Cl-</em>

4.8M Cl- / 4.2 times = 1.14M Cl-

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Dominik [7]

Answer:

9 g/ml

Explanation:

5 + 3.3 = 8.5

But you should use sig figs.

5 has no tenths, hundredths, and etc.

Therefore the 8.5 rounds up to 9

So the answer is 9.

3 0
3 years ago
A can of soda is 335ml what is 2 cans of soda in ml
Snezhnost [94]
I can =335ml
2cans=?

2cans×335ml÷1
= 670ml
5 0
3 years ago
&lt; please help!!! &gt;
svlad2 [7]

Answer:

n = 0.573mol

Explanation:

PV = nRT => n = PV/RT

P = 1.5atm

V = 8.56L

R = 0.08206Latm/molK

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n = (1.5atm)(8.56L)/(0.08206Latm/molK)(273K) = 0.573mol

8 0
3 years ago
If 15.6g of titanium reacts with oxygen to form 20g of titanium oxide what is the mass of oxegen
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4 0
3 years ago
Be sure to answer all parts.
Liula [17]

A. The patch's area in square kilometers (km²) is 1.61×10⁻⁹ km²

B. The cost of the patch to the nearest cent is 734 cents

<h3>A. How to convert 16.1 cm² to square kilometers (km²)</h3>

We can convert 16.1 cm² to km² as illustrated below:

Conversion scale

1 cm² = 1×10⁻¹⁰ km²

Therefore,

16.1 cm² = 16.1 × 1×10⁻¹⁰

16.1 cm² = 1.61×10⁻⁹ km²

Thus, 16.1 cm² is equivalent to 1.61×10⁻⁹ km²

<h3>B. How to determine the cost in cent</h3>

We'll begin by converting 16.1 cm² to in². This can be obtained as illustrated below:

1 cm² = 0.155 in²

Therefore,

16.1 cm² = 16.1 × 0.155

16.1 cm² = 2.4955 in²

Finally, we shall the determine the cost in centas fo r llow:

  • Cost per in² = $2.94 = 294 cent
  • Cost of 2.4955 in² =?

1 in² = 294 cent

Therefore,

2.4955 in² = 2.4955 × 294

2.4955 in² = 734 cents

Thus, the cost of the patch is 734 cents

Learn more about conversion:

brainly.com/question/2139943

#SPJ1

6 0
1 year ago
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