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Shtirlitz [24]
3 years ago
13

List the 4 questions to answer when you find the charge of an ion

Chemistry
1 answer:
LiRa [457]3 years ago
7 0

Answer:

for example what is the ion charge of potassium ion formula ( K)

or  

what is the ion charge of phospate ion formula (PO4)

Explanation:

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A florist prepares a solution of nitrogen-phosphorus fertilizer by dissolving 5.66 g of NH₄NO₃ and 4.42 g of (NH₄)₃ PO₄ in enoug
Alexandra [31]

In finding the molarity of a solution, we use the following formula:

M=moles soluteL solution

What is Molarity?

The number of moles of the solute is calculated by dividing the mass of the solute by its molar mass.

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The molar mass of  NH4NO3 and (NH4)3PO4 are  80.043 g/mol and 149.0867 g/mol, respectively.

molesNH+4inNH4NO3=5.66 g80.043 g/mol×1molNH+41molNH4NO3=0.0707 mol

molesNH+4in(NH4)3PO4=4.42 g149.0867 g/mol×3molNH+41mol(NH4)3PO4=0.0889 mol

total molesNH+4=0.0707 mol+0.0889 mol=0.1596 mol

molesPO3−4in(NH4)3PO4=4.42 g149.0867 g/mol×1molPO3−41mol(NH4)3PO4=0.0296 mol

[NH+4]=0.1596 mol20.0 L=7.98×10−3 M NH+4

[PO3−4]=0.0296 mol20.0 L=1.48×10−3 M PO3−4

Therefore, [PO3−4]\\ has a molarity of  1.48×10−3 M PO3−

To learn more about Molarity click on the link below:

brainly.com/question/19943363

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5 0
1 year ago
प्रश्न 5. 'पुष्प की अभिलाषा' कविता में पुष्प के दवारा क्या अभिलाषा व्यक्त की गई ​
Kay [80]
Please ask in English
4 0
3 years ago
What information is needed to calculate the percent composition of a compound
IrinaVladis [17]

Percent Composition by Mass. Percent composition is calculated from a molecular formula by dividing the mass of a single element in one mole of a compound by the mass of one mole of the entire compound. This value is presented as a percentage.

The best answer. :)

6 0
3 years ago
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joja [24]

Answer:

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4 0
2 years ago
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If I have 251.14 grams of citric acid and calcium bicarbonate mixture how much citrus acid do I have??
Snezhnost [94]
About 255.3 grams is the answer I believe. I just had a school work packet and had that question on it, and that is the answer that I had put on it I believe.
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