2 years ago

Which image illustrates the bouncing of a light wave off of a surface?

Physics

2 answers:

Naily [24]2 years ago

8 0

Answer:

The answer is A good luck :P

DochEvi [55]2 years ago

4 0

Answer:

Explanation:

The light Bounces off because it is reflecting off glass or anything else

You might be interested in

After the pendulum is dropped, determine the height at which the kinetic energy is equal to the potential energy.

Fofino [41]

0.5 m v² = m g h
⇅
h = 0.5 v²/g

4 0

3 years ago

I don’t understand how to do this

anzhelika [568]

Explanation:

A) Use Hooke's law to find the spring constant.

F = kx

40 N = k (0.4 m)

k = 100 N/m

B) Period of a spring-mass system is:

T = 2π √(m / k)

T = 2π √(2.6 kg / 100 N/m)

T = 1 s

Frequency is the inverse of period.

f = 1 / T

f = 1 Hz

5 0

2 years ago

What is one property of iodine

mamaluj [8]

Answer: I2

Explanation:

6 0

2 years ago

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!

Serhud [2]

True,
Explanation: because it’s the same reason that lighting touches the ground/ goes up to the sky, because it is trying to balance out its charges

4 0

3 years ago

Read 2 more answers

If a 0.50-kg block initially at rest on a frictionless, horizontal surface is acted upon by a force of 3.7 N for a distance of 6

mel-nik [20]

The block's velocity is determined as 10.03 m/s.

<u>Explanation:</u>

According to work energy theorem, the work done on an object is equal to the change in kinetic energy of the object.

So, work done = Kinetic energy

$\text {Force } \times \text { displacement }=\frac{1}{2} \times m \times v^{2}$

Thus, the velocity can be determined as

$\text {velocity}=\sqrt{\frac{2 \times \text {Force} \times \text {displacement}}{m}}$

$\text {velocity}=\sqrt{\frac{2 \times 3.7 \times 6.8}{0.50}}=\sqrt{\frac{50.32}{0.50}}=\sqrt{100.64}$

Velocity = 10.03 m/s.

So the block's velocity is determined as 10.03 m/s.

5 0

3 years ago