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Rudik [331]
3 years ago
11

in the figure shown, if the mass of the block is 4kg and the coefficient of static friction is 0.5 and the coefficient of kineti

c friction is 0.3 what is the minimum force F needed to move the block
Physics
1 answer:
Elan Coil [88]3 years ago
3 0

Answer:

Ff = 19.6 N

Explanation:

So since its saying whats the minimum F to move the block, we will use static friction (0.5).

We will use the equation for force of friction, which is Ff = uFn

Ff = (0.5)(4)(9.8)

Ff = 19.6 N

this is the minumum force needed to move the block, as that is the frictional force. You would need to apply a minimum force of 19.6 N to move the block

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By tightening a string you are actually putting more stress on the string you are giving it a new frequency that isn't natural.

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An ice cream maker has a refrigeration unit which can remove heat at 120 Js'. Liquid ice
Rom4ik [11]

Answer:

The amount of heat energy that must be removed from the mixture to cool it to its freezing point, of -16°C is 45,360 J

Explanation:

The given parameters for the refrigeration unit and the ice cream are;

The power of the refrigeration unit = 120 J/s

The mass of the liquid ice cream, m = 0.6 kg

The initial temperature of the liquid ice cream, T₁ = 20°C

The freezing point temperature of the ice cream, T₂ = -16°C

The specific heat capacity of the ice cream, c = 2,100 J/kg⁻¹·°C⁻¹

The amount of heat energy that must be removed from the mixture to cool it to its freezing point, ΔQ, is given as follows;

ΔQ = m × c × ΔT

Where;

ΔT = T₁ - T₂

∴ ΔQ = m × c × (T₁ - T₂)

Therefore, by substituting the known values, we have;

ΔQ = 0.6 × 2,100 × (20 - (-16)) = 45,360

The amount of heat energy that must be removed from the mixture to cool it to its freezing point, of -16°C = ΔQ = 45,360 J.

8 0
2 years ago
If the electron has half the speed needed to reach the negative plate, it will turn around and go towards the positive plate. Wh
In-s [12.5K]

Answer:

 v = -v₀ / 2

Explanation:

For this exercise let's use kinematics relations.

Let's use the initial conditions to find the acceleration of the electron

            v² = v₀² - 2a y

when the initial velocity is vo it reaches just the negative plate so v = 0

           a = v₀² / 2y

now they tell us that the initial velocity is half

          v’² = v₀’² - 2 a y’

          v₀ ’= v₀ / 2

at the point where turn v = 0              

          0 = v₀² /4  - 2 a y '

          v₀² /4 = 2 (v₀² / 2y)  y’

          y = 4 y'

          y ’= y / 4

We can see that when the velocity is half, advance only ¼ of the distance between the plates, now let's calculate the velocity if it leaves this position with zero velocity.

         v² = v₀² -2a y’

         v² = 0 - 2 (v₀² / 2y) y / 4

         v² = -v₀² / 4

         v = -v₀ / 2

We can see that as the system has no friction, the arrival speed is the same as the exit speed, but with the opposite direction.

7 0
3 years ago
When water changes into vapor this is called?
Scorpion4ik [409]

When water changes into vapor, it is called evaporation.  BONUS:  This is formed by the boiling point of water, which is 230°F (Fahrenheit) or 110°C (Celsius).

4 0
2 years ago
Inside a car that was at 273 K, a bottle with a pressure at 100,000 pascals warms up to
Deffense [45]

Answer:

P2 = 128,205 pascal.

Explanation:

<u>Given the following data;</u>

Original Pressure, P1 = 100,000 pascals

Original Temperature, T1 = 273K

New Temperature, T2 = 350K

To find new pressure P2, we would use Gay Lussac' law.

<em>Gay Lussac's law states that when the volume of an ideal gas is kept constant, the pressure of the gas is directly proportional to the absolute temperature of the gas. </em>

Mathematically, Gay Lussac's law is given by;

PT = K

Where;

  • P represents pressure.
  • T represents temperature.
  • K is the constant of proportionality.

\frac{P1}{T1} = \frac{P2}{T2}

<em>Making P2 as the subject formula, we have;</em>

P_{2}= \frac{P1}{T1} * T_{2}

Substituting into the equation, we have;

P_{2}= \frac{100000}{273} * 350

P_{2}= 366.3004* 350

P2 = 128205.13 ≈ 128205 pascal.

<em>Therefore, the pressure inside the hot water bottle is 128,205 pascal. </em>

5 0
2 years ago
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