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3 years ago

If x-12sqrt + 36=0 What is the value of X

Mathematics

1 answer:

NISA [10]3 years ago

6 0

Answer:

boy/girl you are in collage why u asking us its always one step forward and three seps back

Step-by-step explanation:

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Prove divisibility 45^45·15^15 by 75^30

Anuta_ua [19.1K]

Answer:

$3^{75}$

Step-by-step explanation:

We are asked to divide our given fraction: $\frac{45^{45}*15^{15}}{75^{30}}$ .

We will simplify our division problem using rules of exponents.

Using product rule of exponents $(a*b)^n=a^n*b^n$ we can write:

$45^{45}=(3*15)^{45}=3^{45}*15^{45}$

$75^{30}=(5*15)^{30}=5^{30}*15^{30}$

Substituting these values in our division problem we will get,

$\frac{3^{45}*15^{45}*15^{15}}{5^{30}*15^{30}}$

Using power rule of exponents $a^m*a^n=a^{m+n}$ we will get,

$\frac{3^{45}*15^{45+15}}{5^{30}*15^{30}}$

$\frac{3^{45}*15^{60}}{5^{30}*15^{30}}$

Using quotient rule of exponent $\frac{a^m}{a^n}=a^{m-n}$ we will get,

$\frac{3^{45}*15^{60-30}}{5^{30}}$

$\frac{3^{45}*15^{30}}{5^{30}}$

Using product rule of exponents $(a*b)^n=a^n*b^n$ we will get,

$\frac{3^{45}*(3*5)^{30}}{5^{30}}$

$\frac{3^{45}*3^{30}*5^{30}}{5^{30}}$

Upon canceling out $5^{30}$ we will get,

$3^{45}*3^{30}$

Using power rule of exponents $a^m*a^n=a^{m+n}$ we will get,

$3^{45+30}$

$3^{75}$

Therefore, our resulting quotient will be $3^{75}$ .

8 0

2 years ago

PLEASE HELP 25 POINTS!!!

miss Akunina [59]

Sequence: 2 + 1 + 1/2 + 1/4 + 1/8 + ...

Explanation:

Here Given Sum to Infinity

$\sf S \infty \ =a_1 \ x \ \dfrac{1}{1-r}$

Identify following

a1 = 2

r = 1/2

Solve:

$\rightarrow \sf S \infty \ =2 \ x \ \dfrac{1}{1-\frac{1}{2} }$

$\rightarrow \sf S \infty \ =4$

The sum of this infinity series is 4

5 0

1 year ago

Can someone please help me with this? I’ve been struggling with this question for a while and is due soon! I’ll give brainliest

Fofino [41]

Answer: See below

Step-by-step explanation:

The transformation from triangle LMN to triangle L'M'N' is the reflection about the line y =x.

The line segment from L to y=x and the line segment from L' to line y=x are congruent.

Yes, we will get the same characteristic if we draw a line from point M to y=x and the line from M' to y=x.

It is because points P', M' and N' are reflections of points P, M, and N respectively about the line y=x.

Graph 1 (attached as first picture)

Graphing a triangle LMN and reflecting it over the line y = x to create triangle L'M'N, we have:

The transformation from triangle LMN to triangle L'M'N' is the reflection about the line y =x.

Drawing a line from point L to the line y=x and from line L' to line y=x we have:

Graph 2 (attached as second picture)

The line segment from L to y=x and the line segment from L' to line y=x are congruent.

Yes, we will get the same characteristic if we draw a line from point M to y=x and the line from M' to y=x.

It is because points P', M' and N' are reflections of points P, M, and N respectively about the line y=x.

4 0

2 years ago

Evaluate 6(y-6) when y=9.

julia-pushkina [17]

Answer:

Step-by-step explanation:

Substitute 9 as y. 6(9-6). Subtract: 6(3). Multiply: 18

7 0

3 years ago

Read 2 more answers

Two cars leave at the same time from points A and B, the distance between them is 280 km. If the cars meet each other, they’ll m

kykrilka [37]

Set up the following equations:

$2x + 2y = 280$

$14x - 14y = 280$

x represents car A's speed, and y represents car B's speed.

We'll use elimination to solve this system of equations. Multiply the first equation by 7:

$(2x + 2y = 280) * 7 = 14x + 14y = 1960$

$14x - 14y = 280$

Combine both equations:

$28x = 2240$

Divide both sides by 28 to get x by itself:

$x = 80$

The speed of car A is 80 mph.

Since we now know the value of one of the variables, we can plug it into the first equation:

$2(80) + 2y = 280$

$160 + 2y = 280$

Subtract 160 from both sides.

$2y = 120$

Divide both sides by 2 to get y by itself:

$y = 60$

The speed of car B is 60 mph.

7 0

3 years ago