3 years ago

Anyone know how to do this? It’s for Chemisty

1 answer:

7 0

You have to take the top quantity and divide it by the crossponent

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Savatey [412]

Answer = 0.0007 moldm

7 0

3 years ago

GarryVolchara [31]

The answer is true ^-^

6 0

3 years ago

maxonik [38]

Answer: The 234.74 grams of sample should be ordered.

Explanation:

Let the gram of 114 Ag to ordered be $N_o$

The amount required for the beginning of experiment = 0.0575 g

Time requires to ship the sample = 4.2hour = 252 min(1 hr = 60 min)

Half life of the sample = ${t_{\frac{1}{2}}$ = 21 min

$\lambda =\frac{0.693}{t_{\frac{1}{2}}}=\frac{0.693}{21 min}=0.033 min^{-1}$

$\log[N]=\log[N_o]-\frac{\lambda t}{2.303}$

$\log[0.0575 g]=\log[N_o]-\frac{0.033 min^{-1}\times 252 min}{2.303}$

$N_o=234.74 grams$

The 234.74 grams of sample should be ordered.

4 0

3 years ago

lubasha [3.4K]

Answer:

glycerol

Explanation:

it is thick sweet liquid.It is type of alcohol which has 3 OH groups

4 0

2 years ago

elena-s [515]

Its 4 dude i did this already

8 0

2 years ago