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3 years ago

10

Two astronauts (each with mass 70 kg) push off each other in space. One astronaut carries 46.7 kg of equipment and moves away wi

th a speed of 0.3 m/s.
Calculate the velocity of the other astronaut.

2 answers:

shepuryov [24]3 years ago

8 0

<h3>0.062 m/s is the answer! </h3>

Kobotan [32]3 years ago

7 0

Answer:

<h2>Kindly, Refer to the attachment...</h2>

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Which of the following statements about the Coriolis effect is correct?

labwork [276]

Answer:

Option D

The Coriolis effect works at right angles to the direction of airflow

Explanation:

At the equator, Coriolis effect is negligible, basically zero while it's strongest at the poles (to imply statement B is wrong). Moreover, Coriolis effect is affected by the speed of wind and it also affects the speed of wind since when the wind speed decreases, due to friction for example, the Coriolis effect is also reduces.

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3 years ago

Contrast the average speed and the instantaneous speed of runner in a race.

ehidna [41]

Average speed of the runner is the rate at which the runner covers the total distance. Average speed of the runner in the race is given by,

Average speed = $\frac{Total distance}{Total time}$

Where

Total distance = Distance covered by the runner from initial to final position

Total time = time taken by the runner to cover entire distance

Instantaneous speed is the speed of the runner at the particular moment in the given time. Instantaneous speed is given by,

Instantaneous speed = $\frac{dx}{dt}$

x = position of the runner at time t

t = time taken to cover distance x

Hence, Average speed and instantaneous speed are different for a runner running in the race.

6 0

3 years ago

A pulley with a radius of 3.0 cm and a rotational inertia of 4.5 x 10–3 kg∙m2 is suspended from the ceiling. A rope passes over

vekshin1

Answer:

22J

Explanation:

Given :

radius 'r'= 3cm

rotational inertia 'I'=4.5 x $10^{-3}$ kgm²

mass on one side of rope ' $m_{1$ '= 2kg

mass on other side of rope' $m_{2$ ' =4kg

velocity'v' of mass $m_{2$ ' = 2m/s

Angular velocity of the pulley is given by

‎ω = v /r => 2/ 3x $10^{-2$

‎ω = 66.67 rad/s

For the rotating body, we have

KE = $\frac{1}{2}$ I ω²

$KE_p = \frac{1}{2} (4.5 *10^{-3} )(66.67^{2} )$

$KE_p$ = 10J

Next is to calculate kinetic energy of the blocks :

$KE_{b} = \frac{1}{2} (m_1 + m_2).v^2\\KE_b= \frac{1}{2} (2+4).2^2$

$KE_b$ =12J

Therefore, the total kinetic energy will be

KE = $KE_p + KE_b$ =10 + 12

KE= 22J

6 0

3 years ago

A city of punjab has 15 percemt chance of wet weather on any given day. What is probability that it will take a week for it thre

sesenic [268]

Answer:

The probability that it will take a week for it three wet weather on 3 separate days is 0.06166 and its standard deviation is 0.9447

Explanation:

We are given that A city of Punjab has 15 percent chance of wet weather on any given day.

So, Probability of wet weather = 0.15

Probability of not being a wet weather = 1-0.15 =0.85

We are supposed to find probability that it will take a week for it three wet weather on 3 separate days

Total number of days in a week = 7

We will use binomial over here

n = 7

p =probability of failure = 0.15

q = probability of success=0.85

r=3

Formula : $P(r=3)=^nC_r p^r q ^{n-r}$

$P(r=3)=^{7}C_{3} (0.15)^3 (0.85)^{7-3}\\P(r=3)=\frac{7!}{3!(7-3)!} (0.15)^3 (0.85)^{7-3}\\P(r=3)=0.06166$

Standard deviation = $\sqrt{n \times p \times q}$

Standard deviation = $\sqrt{7 \times 0.15 \times 0.85}$

Standard deviation =0.9447

Hence The probability that it will take a week for it three wet weather on 3 separate days is 0.06166 and its standard deviation is 0.9447

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3 years ago

Quick! how did Daniel hale Williams contribute to science?

My name is Ann [436]

He preformed the first ever successful open heart surgery

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3 years ago