Which of the following statements about the Coriolis effect is correct?

Physics

1 answer:

labwork [276]3 years ago

7 0

Answer:

Option D

The Coriolis effect works at right angles to the direction of airflow

Explanation:

At the equator, Coriolis effect is negligible, basically zero while it's strongest at the poles (to imply statement B is wrong). Moreover, Coriolis effect is affected by the speed of wind and it also affects the speed of wind since when the wind speed decreases, due to friction for example, the Coriolis effect is also reduces.

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In a closed system, the loss of momentum of one object ________ the gain in momentum of another object.

Virty [35]

In a closed system, the loss of momentum of one object is same as________ the gain in momentum of another object

according to law of conservation of momentum, total momentum before and after collision in a closed system in absence of any net external force, remains conserved . that is

total momentum before collision = total momentum after collision

P₁ + P₂ = P'₁ + P'₂

where P₁ and P₂ are momentum before collision for object 1 and object 2 respectively.

P'₁ - P₁ = - (P'₂ - P₂)

so clearly gain in momentum of one object is same as the loss of momentum of other object

8 0

3 years ago

(15 points) :^|

mihalych1998 [28]

That is FALSE. The equation to calculate the charges has a distance component that is in the denominator which means that it is inversely proportional (as the distance os greater the force is smaller)

7 0

3 years ago

The force of gravity typically acts in a downward direction on the object on earth when an object is standing still, on the flat

Alja [10]

The normal force acts to counter the gravitational force, that is the upward direction.

5 0

3 years ago

A small truck has a mass of 2145 kg. How much work is required to decrease the speed of the vehicle from 25.0 m/s to 12.0 m/s on

MAXImum [283]

Answer:

The work required is -515,872.5 J

Explanation:

Work is defined in physics as the force that is applied to a body to move it from one point to another.

The total work W done on an object to move from one position A to another B is equal to the change in the kinetic energy of the object. That is, work is also defined as the change in the kinetic energy of an object.

Kinetic energy (Ec) depends on the mass and speed of the body. This energy is calculated by the expression:

$Ec=\frac{1}{2} *m*v^{2}$