From the calculation, the force constant is 192 N. Also, friction would decrease the extension.
<h3>What is the force constant?</h3>
We know that the force constant can be obtained by the use of the relation;
F = Ke
F = applied force
K = force constant
e = extension
We know from Hooks law that the force applied is directly proportional to the extension.
We can write;
F = mgcosθ
F = 43 Kg * 9.8 m/s^2 * sin31°
F = 217 N
K = 217 N/1.13 m
K = 192 N/m
If there is friction between the incline and the crate, it will stretch less because some work will be lost due to friction causing only some fraction of the elastic potential energy to be converted to kinetic energy.
Learn more about Hooke's law:brainly.com/question/14140269
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Answer:
The value of L is 0.3 nm.
Explanation:
Given that,
Energy 
Transmission probability = 10⁻³
We need to calculate the value of L
We know that,
Formula of tunneling probability
....(I)
Where,
....(II)
Where, m = mass of electron
Put the value in equation (II)
From equation (I)
Hence, The value of L is 0.3 nm.
Answer:
With a vector, however, the sign simply tells you about the direction of the vector. If you're travelling with a velocity of 20 km/hr east, it means you're travelling east, and your speed is 20 km/hr.
Answer:
v = 112.424 km / s
Explanation:
Given:
d = 3.84 x 10 ⁸ m , R = 63 x 10³ m , m earth = 5.97 x 10²⁴ kg , G = 6.67 x 10⁻¹¹ N * m² / kg² , v₁ = 14.8 x 10 ³ m / s
Using the equation
KE + PE = initial KE + PE
¹/₂ * m * v₂² - G * m/ R = ¹/₂ * m * v₁² - G * m/(R+d)
v₂² = v₁² + 2*G * m [ 1/R - 1/(R+d) ]
v₂² = 14.8 x 10 ³ m /s + 2 * 6.67 x 10⁻¹¹ N * m² / kg² * 5.97 x 10²⁴ kg [ 1 / 63 x 10³m - 1 / ( 63 x 10³ + 3.84 x 10⁸ m ) ]
v = √ 1.26 x 10¹⁰ m² / s²
v = 112.424 x 10³ m/s
v = 112.424 km / s
