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2 years ago

What is the solution(s) to the equation? Use algebra only, no graphing. (5x + 15)(x - 7) = 0

Mathematics

2 answers:

Otrada [13]2 years ago

7 0

Answer:

x = -3, x = 7

Step-by-step explanation:

( 5x + 15 ) ( x - 7 ) = 0

5x + 15 = 0

5x = -15

x = -3

x - 7 = 0

x = 7

Neko [114]2 years ago

5 0

Answer:

x=−3 or x=7

Step-by-step explanation:

(5x+15)(x-7)=0

5x2−20x−105=0

5(x+3)(x−7)=0

x+3=0 or x−7=0

x=−3 or x=7

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Answer:

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The vertex for this case would be:

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Step-by-step explanation:

For this case we have the following equation given:

$y= x^2 -6x +14$

We can complete the square like this:

$y= x^2 -6x +(\frac{6}{2})^2 +14 -(\frac{6}{2})^2$

And solving we have:

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$y= (x-3)^2 +5$

And we can write the expression like this:

$y-5 = (x-3)^2$

The vertex for this case would be:

$V= (3,5)$

And the minimum for the function would be 3 and there is no maximum value for the function

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