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3 years ago

Why there is no inductive reactance in dc circuits

1 answer:

4 0

when voltage source is connected across an ideal inductor, the current through it is limited by self induced EMF( N.d(phi)/dt).. This EMF opposes its cause by Lenz's law.

When steady dc supply is connected, there is no change of flux and hence no induced EMF is developed and inductive reactance offered to steady DC supply is zero.

At the same time this induced EMF is proportional to rate of change of magnetic flux/voltage, hence the inductive reactance offered is also proportional to frequency of voltage source.

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A truck initially traveling at a speed of 22 m/s increases at a constant rate of 2.4 m/s^2 for 3.2s. What is the total distance

FinnZ [79.3K]

Answer:

82.7 m

Explanation:

u= 22m/s

a= 2.4 m/s^2.

t= 3.2 secs

Therefore the distance travelled can be calculated as follows

S= ut + 1/2at^2

= 22 × 3.2 + 1/2 × 2.4 × 3.2^2

= 70.4 + 1/2×24.58

= 70.4 + 12.29

= 82.7 m

Hence the distance travelled by the truck is 82.7 m

6 0

3 years ago

Um corpo de massa igual a 2kg move-se com velocidade constante num plano horizontal sem atrito, conforme a figura. Em seguida, e

castortr0y [4]

Only answering to ask a question

4 0

3 years ago

A football is kicked from the ground with a velocity of 38m/s at an angle of 40 degrees and eventually lands at the same height.

Anastasy [175]

Initially, the velocity vector is $\langle 38cos(40^{\circ}),38sin(40^{\circ}) \rangle=\langle 29.110, 24.426 \rangle$ . At the same height, the x-value of the vector will be the same, and the y-value will be opposite (assuming no air resistance). Assuming perfect reflection off the ground, the velocity vector is the same. After 0.2 seconds at 9.8 seconds, the y-value has decreased by $4.9(0.2)^2$ , so the velocity is $\langle 29.110, 24.426-0.196 \rangle = \langle 29.110, 24.23 \rangle$ .

Converting back to direction and magnitude, we get $\langle r,\theta \rangle=\langle \sqrt{29.11^2+24.23^2},tan^{-1}(\frac{29.11}{24.23}) \rangle = \langle 37.87,50.2^{\circ}\rangle$

4 0

3 years ago

Pls answer the 15a answer i cant understand it

Maksim231197 [3]

Materials required for the experiment of limiting force borne by string:-

String balance
weights
light strings
weight hanger
pan for spring balance
Sand

Steps of procedure for for the experiment of limiting force borne by string:-

First we have to tie a light string to the fixed support and then tie the other end with the weight hanger consists of weight.
Add additional weight to the hanger again and again. And continue the same until the string is broken.
Note down the weight (x) where the string is broken.
Suspend spring balance to a support.
Tie the light string at the end of the balance and at the other end suspend the pan for spring balance.
Now place the weights (x-100 grams) in pan.
Observe the reading in the spring balance.
Add a small amount of sand in the pan by observing the readings.
same is to be done till the string is broken.

Learn more about limiting force here:- brainly.com/question/11371672

#SPJ1

6 0

1 year ago

When 10 N force applied at 30 degrees to the end of a 20 cm handle of a wrench, it was just able to loosen the nut. What magnitu

fredd [130]

Answer:

Explanation:

To get the magnitude of the force would require to just loosen the nut, if the force apply perpendicularly at the end of the handle, we will have to resolve the force perpendicular to the wrench. Torque is the turning effect of a body or force about a point. It is similar to moments.

Torque = Force * radius

Note that the force must be perpendicular to the wrench. On resolving the force perpendicularly to the wrench, we will have to resolve the force to the vertical.

Fy = Fsinθ

Fy = 10sin30°

Fy = 10 * 0.5

Fy = 5N

Torque = Fy * r

Given Fy = 5N and r = 20cm = 0.2m

Torque = 5 * 0.2

Torque = 1Nm

Hence the magnitude of the force would require to just loosen the nut, if the force apply perpendicularly at the end of the handle is 5N

3 0

3 years ago