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3 years ago

Give a reason why hydroxide ions to an acid solution increase in ph

Chemistry

1 answer:

yanalaym [24]3 years ago

5 0

Answer:

creating new water molecules and lowering the amount of free H+ in the system, thereby raising the overall pH.

Explanation:

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HNO3 + KOH → ____ + _____

natita [175]

Answer:

HNO3 + KOH → _KNO3___ + __H2O___

Explanation:

It's balanced

hope it helps

7 0

3 years ago

Step 5: Measure the Mass of the Water (Iron)

Ede4ka [16]

Answer:

12.42 g

Explanation:

because I saw your laptop so it is

7 0

1 year ago

What is the lead concentration of a saturated solution of lead(II) sulfate containing 0.020 M Na2SO4? Ksp for PbSO4 = 6.3x10-7.

labwork [276]

Answer:

i want to help but i d k. the answer :( sorry i couldnt help

Explanation:

8 0

3 years ago

In a reaction 4 NH3 + 5 O2 → 4 NO + 6 H2O, 1 mole of ammonia reacts with 2 moles of oxygen. Which of these is correct after the

Vsevolod [243]

Answer:

Option B) All the ammonia is consumed

Explanation:

1. Balanced chemical equation (given):

$4NH_3+5O_2\rightarrow 4NO+6H_2O$

2. Theoretical mole ratios:

$4molNH_3:5molO_2:4molNO:6H_2O$

3. Limiting reactant:

When 1 mole of ammonia is combined with 2 moles of oxygen, the mole ratio is:

$1molNH_3:2molO_2$

Hence, one of the reactants will be completely consumed (the limiting reactant) and, after completion, an excess of the other will remain unreacted.

You need to compare the the actual ratio with the theoretical ratio.

4/5 > 1/2

Hence, NH₃ is in less proportion with respect to oxygen than what is theoretically needed, and the former is the limiting reactant.

Therefore, the 1 mole (all) of ammonia will be consumed, while some oxygen will remain as excess. This is described by the option B) All the ammonia is consumed.

4. Analyze the other options:

The amount of oxygen that will react is:

$1molNH_3\times5molO_2/4molNH3=5/4molO_2$

And the amount that will remain is:

$2molO_2-4/5molO_2=6/5molO_2$

Neither option A) nor C) describe that situation.

The amount of water produced is:

$1molNH_3\times 6molH_2O/4molNH_3=1.5molH_2O$ , which is not described by the option D).

Hence, the correct answer is the option B) All the ammonia is consumed.

6 0

3 years ago

At 1023 K and 1 atm, a 3.00 gram sample of Snoz(s) (gram-formula mass = 151 g/mol) reacts with hydrogen gas to produce tin and w

Blizzard [7]

Answer:

2 moles of Sn are produced when 4 moles of H2(g) are consumed completely

Explanation:

to determine the number of moles of sn (l) produced when 4.0 moles of H2 (g) is consumed completely.

First, find the number of moles of H2 consumed by taking this as limiting reagent.

$n = \frac{g}{M.W (g/mol)}$

Then find the moles of Sn (l) taking into account the stoichiometric relationship between H2(g) and Sn(l). 2:1

$SnO_{2}$ (s) + 2 $H_{2}$ (g) ⇒ Sn(l) + 2 $H_{2}O$ (g)

$mol Sn(l) = \frac{1mol Sn}{2mol H_{2} } . 4 mol H_{2} = 2 mol$

∴2 moles of Sn are produced when 4 moles of H2(g) are consumed completely.

4 0

3 years ago