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REY [17]
3 years ago
13

Give a reason why hydroxide ions to an acid solution increase in ph

Chemistry
1 answer:
yanalaym [24]3 years ago
5 0

Answer:

creating new water molecules and lowering the amount of free H+ in the system, thereby raising the overall pH.

Explanation:

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HELP PLEASE I WILL GIVE 100 PONTS
pochemuha

Answer:

boiling point

Explanation:

5 0
3 years ago
Read 2 more answers
Rb2co3(aq)+fec2h302(aq)-->
nata0808 [166]

Answer:

Rb2CO3(aq)+Fe(C2H3O2)2(aq)--> 2Rb(C2H3O2)(aq) + FeCO3(s)

Explanation:

The reaction shown in the answer is the reaction of rubidium carbonate and iron II acetate. Rubidium is far more reducing than Fe II hence it can displace Fe II from its salt as shown.

The reducing property of metals depends on the value of their individual electrode potential values. For rubidium, its standard reduction potential is -2.98 V while that of Fe II is -0.44V. Hence rubidium can displace Fe II from its salt as shown above.

4 0
3 years ago
Dna is made up of nitrogenous base pairs. the bases bond in which of the following patterns?
Anit [1.1K]
The nitrogenous bases on the two strands of DNA pair up, purine with pyrimidine (A with T, G with C), and are held together by weak hydrogen bonds. Watson and Crick discovered that DNA had two sides, or strands, and that these strands were twisted together like a twisted ladder -- the double helix.Mar
6 0
2 years ago
How many moles in 28 grams of CO2?
Phantasy [73]

# moles = mass / Mr

moles = 28 / (12+(16*2))

#moles = 28/44

#moles = 0.63 moles

4 0
3 years ago
If 0.213 moles of argon occupies a volume of 652 mL at a particular temp and pressure, what volume would it occupy if 0.162 mole
Andreas93 [3]

Answer:

V₂  = 495.89 mL

Explanation:

Given data:

Initial number of moles = 0.213 mol

Initial volume = 652 mL

Final number of moles = 0.162 mol

Final volume = ?

Solution:

V₁/n₁    =    V₂/n₂

By putting values,

652 mL/0.213 mol   =  V₂ /0.162 mol

V₂  = 652 mL 0.162 mol /0.213 mol

V₂  = 105.62 mL.mol /0.213 mol

V₂  = 495.89 mL

3 0
2 years ago
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