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statuscvo [17]
3 years ago
13

The plant food contains nh4)3po4 what tests would you run to verify the presence of the nh4 ion and the po4 ion

Chemistry
2 answers:
algol133 years ago
8 0

For the presence of ammonium ion, there is a need to add sodium hydroxide solution to the water and warm the mixture. Test any vapor that gets produced with damp red litmus paper. It should turn blue as ammonia gas is discharged, which is alkaline. The ionic equation for the reaction is:  

NH₄⁺ + OH⁻ ⇒ NH₃ + H₂O

For the presence of phosphate ions, the addition of barium ions is done. The ionic equation is:  

3Ba₂⁺ + 2PO4³⁻ ⇒ Ba₃ (PO₄)₂ (precipitate)


exis [7]3 years ago
7 0
<h2>Answer with Explanation </h2>

To Check The Presence Of NH4+ Ion, by making essential with NaOH, and testing the exhaust radiated with wet red litmus paper, the alkali radiated will change its shading to blue.

(you ought to likewise have the capacity to smell the alkali)

NH+ and OH - > H2O and NH3 (g)

To Check The Presence Of The PO43-Ion, by including AgNO3 and seeing the generation of the splendid yellow Ag3PO4 accelerate, which at that point will "disintegrate" when by making the arrangement acidic with abundance HNO3,

(AgI will likewise ppt yellow, yet does not break down when fermented)

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What is the h+ concentration for an aqueous solution with poh = 3.35 at 25 ∘c? express your answer to two significant figures an
RSB [31]
POH value was calculated by the negative logarithm of hydroxide ion concentration.
To know the hydrogen ion concentration, we need to know the pH value, that can be found out if pOH is known 
pH + pOH = 14
pH = 14 - pOH 
pH = 10.65
once the pH is known we have to find the antilog. 
[H⁺] = antilog (-pH)
antilog can be found by 
[H⁺] = 10^(-10.65)
[H⁺] = 2.2 x 10⁻¹¹ M
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The process where substance react with oxygen is called combustion.

Explanation:

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I hope you understand my working:
1) Finding the mol of NH3 to find the mol of (NH4)2SO4 (ammonium sulfate)
2) Mr of (NH4)2SO4
3) Theoretical yield: The actual grams of (NH4)2SO4 produced when reacting 0.514 mol of NH3 to 0.514 mol H2SO4
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Explanation:

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