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3 years ago

8

Which hydrocarbon name adheres correctly to the IUPAC naming system? 3–ethyl–2,4–dimethylhexane 3–methethyl–2,dimethylhexane 4–d

imethylhexane–3–ethyl 4–dimenthylhexane, 3–ethyl

1 answer:

faltersainse [42]3 years ago

4 0

3–ethyl–2,4–dimethylhexane

CH₃-CH(CH₃)-CH(C₂H₅)-CH(CH₃)-CH₂-CH₃

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Answer: The mass of aluminium sample is 55.4 gram

Explanation:

$Q_{absorbed}=Q_{released}$

As we know that,

$Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})$

$m_1\times c\times (T_{final}-T_1)=-[m_2\times c\times (T_{final}-T_2)]$

where,

$m_1$ = mass of aluminium = ?

$m_2$ = mass of water = 300.0 g

$T_{final}$ = final temperature = $23.8^0C$

$T_1$ = temperature of aluminium = $94.5^oC$

$T_2$ = temperature of water = $21.0^oC$

$c_1$ = specific heat of aluminium = $0.897J/g^0C$

$c_2$ = specific heat of water = $4.184J/g^0C$

Now put all the given values in equation (1), we get

$-[m_1\times c_1\times (T_{final}-T_1)]=[m_2\times c_2\times (T_{final}-T_2)]$

$-[m_1\times 0.897\times (23.8-94.5)^0C]=[300.0g\times 4.184\times (23.8-21.0)]$

$m_1=55.4g$

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