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3 years ago

What is the volume of a cone with a radius of 3 feet and a height of 6 feet? Use 3.14 for pi. Round your answer to the nearest h

undredth. A 18.31 ft B 40.25 ft C 56.52 ft D 60.34 ft

Mathematics

1 answer:

Iteru [2.4K]3 years ago

5 0

$\bf \textit{volume of a cone}\\\\
V=\cfrac{\pi r^2 h}{3}~~
\begin{cases}
r=radius\\
h=height\\
-----\\
r=3\\
h=6
\end{cases}\implies V=\cfrac{\pi (3)^2(6)}{3}\implies V=18\pi$

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The length of the brace required is 4.3m

What is sine rule?

In a ΔABC a, b and c are the sides and A, B and C are angles then,

$\frac{a}{SinA}=\frac{b}{sinB}=\frac{c}{sinC}$

We can find the length, l as shown below:

Let AB=3m, BC=2m and AC=l

Let ∠A=25°

So, in ΔABC

$\frac{BC}{sinA}=\frac{AB}{sinC}=\frac{AC}{SinB}$

$\frac{BC}{sinA}=\frac{AB}{sinC}$

$\frac{2}{sin25}=\frac{3}{sinC}$

$\angle{C}=sin^{-1}(\frac{3\times sin25}{2} )$

∠C=39.34°

∠A+∠B+∠C=180°

∠B=180°-25°-39.34°

∠B=115.66°

$\frac{BC}{sinA}=\frac{AC}{SinB}$

$\frac{2}{sin25}=\frac{l}{sin(115.66)}$

$l=\frac{2\times sin(115.66)}{sin25}$

l=4.2659

Rounding to nearest tenth of meter.

l=4.3m

Hence, the length of the brace required is 4.3m

Learn more about Sine Rule here:

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