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drek231 [11]
3 years ago
14

suppose you have a solution that might contain any or all of the following cations: Cu2+, Ag+,Ba2+ and Mn2+. The addition of HBr

causes a precipitate form. after the precipitate is separated by filtration, H2SO4 is added to the supernatant liquid, and another precipitate forms.
Chemistry
2 answers:
MAVERICK [17]3 years ago
8 0

The solution formed a precipitate when HBr is added. This indicates that the cation present would be silver ion(Ag^{+}) as silver forms an insoluble precipitate with bromide ion.

The equation representing the formation of silver bromide precipitate is:

Ag^{+}(aq)+HBr(aq)-->AgBr(s)+H^{+}(aq)

Bromides of all the other cations,Cu^{2+},Ag^{+},Ba^{2+},Mn^{2+}are soluble in aqueous solutions.

After removing the precipitate of AgBr by filtration, the supernatant solution is treated with H_{2}SO_{4}and another precipitate forms. This would be due to the presence of Ba^{2+}ions as barium sulfate is an insoluble precipitate.

The equation representing the formation of barium sulfate precipitate is:

Ba^{2+}(aq)+H_{2}SO_{4}(aq)-->BaSO_{4}(s)+2H^{+}(aq)

vitfil [10]3 years ago
5 0
Of the given cations, only Ag+ forms both an insoluble bromide and sulfate, leading to precipitatoin; therefore, the ion present must be Ag+.
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