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Citrus2011 [14]
3 years ago
14

125mm hg into atmosphere

Chemistry
1 answer:
alexdok [17]3 years ago
7 0

Answer:

Explanation:

1atm=760mmHg

Therefore, 125mmHg = 125/760 = 0.164atm

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2 bromocyclopentanamine structural formula
Elis [28]

Answer:

The structure is given in attached file.

Explanation:

Explanation

2-bromocyclopentamine (Figure attached) is a synthetic compound which is synthesized by substitution reaction of cyclopentamine and hydrobromide. Its molecular formula and molecular mass are C5H10NBr and 164.05 mol/g respectively.  It is a very reactive compound so it doesn’t available in pure form, it is present in market as a mixture of 2-bromocyclopentamine and Hydrobromide.

Properties :

Its boiling point is 115 0C

Its melting point is – 75 oC

It is highly flammable

It is highly toxic

It is irritant

It is corrosive in nature

5 0
3 years ago
The equilibrium for the reaction between (ch3)2nh a weak base
nadezda [96]

The equilibrium for the dissolution of the weak base is ;(CH3)2NH(aq) + H2O(l) ⇄ (CH3)2NH3^+(aq) + OH^-(aq)

<h3>What is a weak base?</h3>

A weak base is one that does not ionize completely in solution. As such, a weak base will have a very low base dissociation constant Kb reflecting its minimal dissociation in solution.

The question is incomplete hence we are are unable to work out the equilibrium but in solution it will look like this;

(CH3)2NH(aq) + H2O(l) ⇄ (CH3)2NH3^+(aq) + OH^-(aq)

Learn more about weak base: brainly.com/question/4131966

7 0
2 years ago
How many grams of aluminum chloride are needed to react completely with 1.084g lithium sulfide?
Oksi-84 [34.3K]
Molar mass :

Li₂S = <span>45.947 g/mol

AlCl</span>₃ = <span>133.34 g/mol

</span><span>3 Li</span>₂<span>S + 2 AlCl</span>₃<span> = 6 LiCl + Al</span>₂S₃

3 * 45.947 g Li₂S ----------> 2 * <span>133.34 g AlCl</span>₃
1.084 g Li₂S ----------------> ?

Mass Li₂S = 1.084 * 2 * 133.34 / 3 * 45.947

Mass Li₂S = 289.08112 / 137.841

Mass Li₂S = 2.0972 g 

hope this helps!

5 0
3 years ago
Which physical property can NOT be observed using 5 senses without changing the chemical makeup of the object that you are obser
bonufazy [111]
Ummm i believe it’s C
4 0
3 years ago
If your lawn is 21.0 ft wide and 20.0 ft long, and each square foot of lawn accumulates 1350 new snow flakes every minute. How m
klemol [59]
Let us start with the total area of the lawn. Area= width x length, ie, 21 x 20 = 420 sq. ft.   Snow flakes per square foot per minute = 1350  So Snow flakes for 420 sq.feet per minute = 420 x 1350 = 567000.   Snow flakes for 1 hour = 567000 x 60 = 34020000 (60 minutes)  Weight of 34020000 snow flakes = 34020000 x 1.60 = 54432000mg.  To convert it into kilograms, divide this number by 1000000 (1 kilogram = 1000000 milligrams)  Thus 54432000/1000000 = 54.432 kilograms or 54 kilograms and 432 grams.
6 0
3 years ago
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