Answer:
R1= 288032.53cy
Explanation:
For the Other part of the question, since the water content embankment is less than eater content of borrow material And it doesn't require any extra quantity of water bearing in mind that there is no evaporation, hence no further loss of water.
Answer:
The volumetric flow rate through the slot is 0.05472 m^3/s
Explanation:
Volumetric flow rate = peak velocity × slot width × slot height
Peak velocity = 0.8 m/s
Slot width = 114 mm = 114/1000 = 0.114 m
Slot height = 0.6 m
Volumetric flow rate = 0.8 m/s × 0.114 m × 0.6 m = 0.05472 m^3/s
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Answer:
All 3 principal stress
1. 56.301mpa
2. 28.07mpa
3. 0mpa
Maximum shear stress = 14.116mpa
Explanation:
di = 75 = 0.075
wall thickness = 0.1 = 0.0001
internal pressure pi = 150 kpa = 150 x 10³
torque t = 100 Nm
finding all values
∂1 = 150x10³x0.075/2x0,0001
= 0.5625 = 56.25mpa
∂2 = 150x10³x75/4x0.1
= 28.12mpa
T = 16x100/(πx75x10³)²
∂1,2 = 1/2[(56.25+28.12) ± √(56.25-28.12)² + 4(1.207)²]
= 1/2[84.37±√791.2969+5.827396]
= 1/2[84.37±28.33]
∂1 = 1/2[84.37+28.33]
= 56.301mpa
∂2 = 1/2[84.37-28.33]
= 28.07mpa
This is a 2 d diagram donut is analyzed in 2 direction.
So ∂3 = 0mpa
∂max = 56.301-28.07/2
= 14.116mpa