Answer:
C: Viscosity, the resistance to flow that fluids exhibit 
Explanation:
Did it on Edge :)
 
        
             
        
        
        
 Answer:
a) 280MPa
b) -100MPa
c) -0.35
d) 380 MPa
Explanation:
GIVEN DATA:
mean stress 
stress amplitude 
a) 
      --------------1
 --------------1
 
     -----------2
 -----------2
solving 1 and 2 equation we get

b) 
c)
stress ratio

d)magnitude of stress range 
                       
                        = 280 -(-100) = 380 MPa
 
        
             
        
        
        
Answer:
The break force that must be applied to hold the plane stationary is 12597.4 N
Explanation:
p₁ = p₂, T₁ = T₂
 

The heat supplied =  × Heating value of jet fuel
 × Heating value of jet fuel
The heat supplied = 0.5 kg/s × 42,700 kJ/kg = 21,350 kJ/s 
The heat supplied =  ·
 ·  
 
  = 20 kg/s
 = 20 kg/s
The heat supplied = 20* = 21,350 kJ/s
 = 21,350 kJ/s
 = 1.15 kJ/kg
 = 1.15 kJ/kg
T₃ = 21,350/(1.15*20) + 485.03 = 1413.3 K
p₂ = p₁ × p₂/p₁ = 95×9 = 855 kPa
p₃ = p₂ = 855 kPa
T₃ - T₄ = T₂ - T₁ = 485.03 - 280.15 = 204.88 K
T₄ = 1413.3 - 204.88 = 1208.42 K
 
T₅ = 1208.42*(2/2.333) = 1035.94 K
 = √(1.333*287.3*1035.94) = 629.87 m/s
 = √(1.333*287.3*1035.94) = 629.87 m/s
The total thrust =  ×
 ×  = 20*629.87 = 12597.4 N
 = 20*629.87 = 12597.4 N
Therefore;
The break force that must be applied to hold the plane stationary = 12597.4 N.