From a to b speed is 600+40 = 640
from b to a speed is 600-40 = 560
let t be the number of hours of flight. This would mean it would have traveled a distance of 640 miles and the distance yet to travel is 2400-640t
Time left will be (2400-640t)/640. But if they were to return to a it would fly 640t miles at 560mph which will take (640t/560) hrs
(2400-640t) / 640 = 640t / 560
560(2400 - 640t) = 640t x 640
t = 1.75hrs
Answer:

Explanation:
Let´s find the capacitor impedance:

Using the data provided:
Ω
Now let´s find the capacitance:

μF
We can calculate the capacitor impedance for the second case:
Ω
Finally we can calculate the voltage of the second generator:

Explanation:
It is given that,
Wavelength of a beam of light in vacuum, 
(a) Let v is the speed of light in a liquid whose index of refraction at this wavelength is 1.56.
We know that,
Refractive index,

(b) The wavelength of light in material,

Let
is the wavelength of these waves in the liquid. So,

Hence, this is the required solution.
Answer:
what is the question please?