It is 25 miles from your house to a friend's house. Which unit conversion

You are a meteorologist. While taking present weather observations, you note that the sky is full of wispy cirrus clouds estimat

Goshia [24]

Answer:

It will take 60 hours to pass your area

Explanation:

From the question we are told that

The the distance of wispy cirrus clouds is $d_w =6km = 6*10^3 m$

The slope is given as $S = 1:300 = \frac{1}{300}$

The speed is $v = 40km/hour$

Since the slope is 1:300 which indicates the change in the distance of the wispy cirrus clouds overhead to the distance of the warm front

Now if

1 km → 300 km

Then

$8km$ → x km

Cross multiplying and making x the subject

$x = 8 *300 = 2400 \ km$

Velocity is mathematically denoted as

$velocity(v) = \frac{Distance(d) }{Time(t) }$

Now making time the subject

$Time (t) = \frac{Distance }{Velocity}$

Now substituting values we have

$t =\frac{2400}{40}$

$= 60\ hours$

8 0

3 years ago

What is the maximum velocity (in m/s) of electrons ejected from a material by 85 nm photons, if they are bound to the material b

diamong [38]

The maximum velocity of electrons is v = 3.20 × 10¹⁵ m/s

The wavelength of photons λ = 85 nm

W = 4.66 ev

<h3>What is photoelectric effect and how velocity of photoelectrons is calculated?</h3>

The emission of electrons happened and absorbed through the electromagnetic radiation is said to be photoelectric effect.

Photoelectric cells, photodiodes works on the principle of photoelectric effect.

According to of photoelectric effect,

E = hν

Here, hc / λ = W + KE max

hc / λ = W + 1/2 mv² max

v² = sqrt of (( hc / λ - W) (2/m))

I cap denotes λ ,

substituting all the values,

v = sqrt of ( (6.623 × 10⁻³⁴ Js ) ( 3 × 10⁸ m/s) / (85 nm) - 4.66ev) (2/ 9.1× 10⁻³¹

v = sqrt of ((1.987800 × 10⁻²⁵ / 85 × 10 ⁹ ) - 4.66 ev ) ( 2.197 × 10³⁰)

v = sqrt of ((2.338588 × 10⁻³⁶) - 4.66 ev ) ( 2.197 × 10³⁰)3.2

v = 3.20 × 10¹⁵ m/s

Thus, the maximum velocity is calculated as v = 3.20 × 10¹⁵ m/s.

Learn more about photoelectric effect,

brainly.com/question/1895423

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4 0

2 years ago

A mass resting on a horizontal, frictionless surface is attached to one end of a spring; the other end is fixed to a wall. It ta

Marina CMI [18]

Answer:

(a) The spring constant is 426N/m

(b) The mass is 5.65kg

Explanation:

(a) Energy stored in the spring (E) = 3.6J, extension (e) = 0.13m

E = 1/2Ke^2

3.6 = 1/2 × K × 0.13^2

K (spring constant) = 3.6×2/0.0169 = 426N/m

(b) F = Ke = 426 × 0.13 = 55.38N

Assuming the maximum acceleration (a) is 9.8m/s^2

Mass (m) = F/a = 55.38/9.8 = 5.65kg

7 0

3 years ago

A small block with mass 0.0350 kgkg slides in a vertical circle of radius 0.550 mm on the inside of a circular track. During one

Lisa [10]

Answer:

W_net = μ 5.58, μ = 0.1 W_net = 0.558 J

Explanation:

The work is defined by the related

W = F. d = F d cos θ

where bold indicates vectors.

In the case, the work of the friction force on a circular surface is requested.

The expression for the friction force is

fr = μ N

the friction force opposes the movement, therefore the angle is 180º and the cos 180 = -1

W = - fr d

the path traveled half the length of the circle

L = 2 π R

d = L / 2

d = π R

we substitute

W = - μ N d

Total work is initial to

W_neto = - μ π R (N_b - N_a)

let's calculate

W_net = - μ π 0.550 (0.670 - 3.90)

W_net = μ 5.58

for the complete calculation it is necessary to know the friction coefficient, if we assume that μ = 0.1

W_net = 0.1 5.58

W_net = 0.558 J

7 0

3 years ago

What type of equilibrium is guaranteed by each condition of equilibrium

Ostrovityanka [42]

Answer: Conditions for equilibrium require that the sum of all external forces acting on the body is zero (first condition of equilibrium), and the sum of all external torques from external forces is zero (second condition of equilibrium). These two conditions must be simultaneously satisfied in equilibrium

Explanation: Hope this helped

5 0

3 years ago