Answer:
1.654 atm.
Explanation:
- We can use the general law of ideal gas: <em>PV = nRT.</em>
where, P is the pressure of the gas in atm.
V is the volume of the gas in L.
n is the no. of moles of the gas in mol.
R is the general gas constant,
T is the temperature of the gas in K.
- If n and V are constant, and have different values of P and T:
<em>(P₁T₂) = (P₂T₁)</em>
<em></em>
P₁ = 1.0 atm, T₁ = 25°C + 273 = 298 K,
P₂ = ??? atm, T₂ = 220°C + 273 = 493 K,
- Applying in the above equation
<em>(P₁T₂) = (P₂T₁)</em>
<em></em>
<em>∴ P₂ = (P₁T₂)/(T₁) </em>= (1.0 atm)(493 K)/(298 K) = <em>1.654 atm.</em>
Answer:
b.Rearrange the two equations to make each variable the focus (you will end up with three variations for each equation).
These oppositely charged compounds are strongly held by electrostatic forces of attraction as these be together for a long time the rise in temparature occurs so that the the melting points rises in them.
The number of students is your independent variable
The expected speed is v = 85.5 km/h
v = 85.5 km/h = (85.5 km/h)*(0.2778 (m/s)/(km/h)) = 23.75 m/s
If there is an uncertainty of 2 meters in measuring the position, then within a 1-second time interval:
The lower measurement for the speed is v₁ = 21.75 m/s,
The upper measurement for the speed is v₂ = 25.75 m/s.
The range of variation is
Δv = v₂ - v₁ = 4 m/s
The uncertainty in measuring the speed is
Δv/v = 4/23.75 = 0.1684 = 16.84%
Answer: 16.8%
