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ivanzaharov [21]
4 years ago
6

What forces shape the stars in galaxies? (Astronomy question, but didn't fit into any categories) PLEASE 

Physics
1 answer:
MaRussiya [10]4 years ago
4 0

Answer:

Force of gravity

Explanation:

when the force of gravity pulls large gas clouds and dust together, the concentrated gas clouds and dust collapse under the force of gravity forming stars.

There are many galaxies out there in the universe, each galaxy has its own solar systems, stars, and collection of gas and dust. We (earth) belong to the Milky Way galaxy, our galaxy got this name from the Romans. They called in 'via lactea', which directly translates to 'road of milk' because of the milky patch they saw at night.

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if i release one steel ball from the top of a ramp and the other ball from the 40cm mark will they have the same acceleration?
solniwko [45]

Answer:

Yes, they will also have the same acceleration. Acceleration is controlled by the amount of weight (def. amount of gravitational pull on a given object) that the ball has. For one ball to accelerate quicker than the other, it would need a propulsion element, which it does not.

Explanation:

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2 years ago
Mike is watching a Disney movie with his son Jason Jason likes the movie so much that he becomes excited and stands in front of
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3 years ago
An object is 40cm from concave mirror and the image is formed 60cm from mirror calculate the focal length of mirror?
Elden [556K]

Answer: the answer is 100 focal length.

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3 years ago
Which of the following was/were used by the Greek philosophers in
Assoli18 [71]

Answer:

a and c are both correct

Explanation:

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5 0
4 years ago
A spring with spring constant k is suspended vertically from a support and a mass m is attached. The mass is held at the point w
garik1379 [7]

Answer:

The oscillation frequency of the spring is 1.66 Hz.

Explanation:

Let m is the mass of the object that is suspended vertically from a support. The potential energy stored in the spring is given by :

E_s=\dfrac{1}{2}kx^2

k is the spring constant

x is the distance to the lowest point form the initial position.

When the object reaches the highest point, the stored potential energy stored in the spring gets converted to the potential energy.

E_P=mgx

Equating these two energies,

\dfrac{1}{2}kx^2=mgx

\dfrac{k}{m}=\dfrac{2g}{x}.............(1)

The expression for the oscillation frequency is given by :

f=\dfrac{1}{2\pi}\sqrt{\dfrac{k}{m}}

f=\dfrac{1}{2\pi}\sqrt{\dfrac{2g}{x}} (from equation (1))

f=\dfrac{1}{2\pi}\sqrt{\dfrac{2\times 9.8}{0.18}}

f = 1.66 Hz

So, the oscillation frequency of the spring is 1.66 Hz. Hence, this is the required solution.

8 0
4 years ago
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