Answer:
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Answer:
Electric field E = kQ/r^2
Distance between charges = 6.30 - (-4.40) = 10.70m
Say the neutral point, P, is a distance d from q1. This means it is a distance (10.70 - d) from q2.
Field from q1 at P = k(-9.50x^10^-6) / d^2
Field from q2 at P = k(-8.40x^10^-6) / (10.70-d)^2
These fields are in opposite directions and are equal magnitudes if the resultant field = 0
k(-9.50x^10^-6) / d^2 = k(-8.40x^10^-6) / (10.70-d)^2
9.50 / d^2 =8.40 / (10.70-d)^2
d^2 / (10.70-d)^2 = 9.50/8.40 = 1.131
d/(10.70-d) = sqrt(1.1331) = 1.063
d = 1.063 ((10.70-d)
= 10.63 - 1.063d
2.063d = 10.63
d = 5.15m
The y coordinate where field is zero is 6.30 - 5.15 = 1.15m
Explanation:
Answer:
1/6 del peso en la tierra.
-- Change the battery to one with higher voltage.
-- Wrap more turns of wire around the spike.
-- If the spike is made of anything else but iron, replace it with a pure iron one.
To solve this problem we use an amplification formula for divergent lenses
Where:
i: distance of the image to the lens
o: Distance from the object to the lens
h = height of the object
h '= height of the image
h '= 6 mm
The height is 6 mm
