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Shkiper50 [21]
3 years ago
5

Liquid Mercury has a density of 13.55 g/cm3 at room temperature (20.0 ° C).

Chemistry
1 answer:
yawa3891 [41]3 years ago
6 0

Answer:

A long glass tube with one end open and the other end sealed was completely filled with mercury, then it was stood on end with the open end in a container filled with mercury.

 

If the tube is relatively short, it will still be filled with mercury all the way to the top.  If it's long enough, the column of mercury will not reach the top.  The air pressure on the surface of the mercury pool that the tube sits in is what supports the mercury. When the weight of a 1 cm^2 column of mercury is greater than the air pressure per cm^2, it can't be supported by that pressure.  The top of the tube will have an almost perfect vacuum, with only a tiny amount of mercury vapor in it.

 The height of a column of water or mercury that can be supported by air pressure depends on, and is proportional to, the density of the water or mercury.

 

How you're supposed to get the answers depends on what units are used to define 1 bar of pressure. Your textbook or lecture notes should give you the value and units of a bar. If you're supposed to look it up, you'll find a variety of different combinations, including 750.06 mm of Hg or 1019.72cm of H 2 O. That would actually give you the answers directly.    

750.06 m m ≈ 0.75 m of H g

1019.72 c m ≈ 10.20 m of water

 

If you're supposed to calculate everything, you'll need to use 1 bar = 1 x 105 N / m 2. Then you'll have to look up the g r a v i t a t i o n constant and calculate the weight of a column of mercury or water. Note that g rams and k i l o g r a m s are units of mass, not weight, which is a force.  The unit of force in the m e t r i c system is the N e w t o n. This is confusing because we measure weight in pounds, which is a force. Most of the rest of the world measures "weight" in k i l o g r a m s, which is really mass.

 

How is 1 bar defined for you?

If it's m m H g, just multiply that by 13.6 to get the height for a column of water.

If it's a force per unit area:

We can calculate the force (weight) of H. g using the g r a v i t a t i o n constant and the given density, then go from there."

Explanation:

I do not own this information

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The equilibrium constant for A + 2B → 3C is 2.1 * 10^-6
Mariana [72]

Answer:

b- 4.4 * 10^-12.

Explanation:

Hello.

In this case, as the reaction:

A + 2B → 3C

Has an equilibrium expression of:

K_1=\frac{[C]^3}{[A][B]^2}=2.1x10^{-6}

If we analyze the reaction:

2A + 4B → 6C

Which is twice the initial one, the equilibrium expression is:

K_2=\frac{[C]^6}{[A]^2[B]^4}

It means that the equilibrium constant of the second reaction is equal to the equilibrium constant of the first reaction powered to second power:

K_2=K_1^2

Thus, the equilibrium constant of the second reaction turns out:

K_2=(2.1 * 10^{-6})^2\\\\K_2=4.4x10^{-12}

Therefore, the answer is b- 4.4 * 10^-12.

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b its radiant energy that heats up the earth.

Explanation:

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What is the ph of 0.450 m al(no3)3 [ka for al3+(aq) = 1.00x10-5]? express your answer to two decimal places?
White raven [17]

Answer : The pH of the solution is, 2.67

Explanation :

The equilibrium chemical reaction is:

                           Al^{3+}+H_2O\rightarrow Al(OH)^{2+}+H^+

Initial conc.       0.450                   0               0

At eqm.           (0.450-x)                 x               x

As we are given:

K_a=1.00\times 10^{-5}

The expression for equilibrium constant is:

K_a=\frac{(x)\times (x)}{(0.450-x)}

Now put all the given values in this expression, we get:

1.00\times 10^{-5}=\frac{(x)\times (x)}{(0.450-x)}

x=0.00212M

The concentration of H^+ = x = 0.00212 M

Now we have to calculate the pH of solution.

pH=-\log [H^+]

pH=-\log (0.00212)

pH=2.67

Therefore, the pH of the solution is, 2.67

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4 years ago
The density of Diamond is 3.51 g/cm3, and the density of platinum is 21.43 g/cm3. If equal masses of diamond and platinum are tr
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Answer:

Explanation:

Diamond has lesser density than platinum . So , if we take equal mass of both , the volume of mass of platinum will be far less .

The density of both diamond and platinum are  more than water so both of them will be drowned in water completely . They will not float . On being drowned , platinum will displace lesser volume of water because of its less volume . So volume change in case of platinum mass will be far less . The volume change for diamond will be more because of its bigger size.

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