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koban [17]
3 years ago
7

In the velocity and acceleration are in the same direction the speed of the object decreases

Physics
1 answer:
DiKsa [7]3 years ago
7 0

Answer:

False

Explanation:

Im pretty sure the answer is false

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Two pebbles, Pebble A and Pebble B, are thrown horizontally with the same force. Pebble A's mass is 3 times the
Hitman42 [59]

Answer:

Pebble A has 1/3 the acceleration as pebble B.

Explanation:

F = m×a

mass of a = 3 × mass of b (m_a = 3 × m_b)

Same starting force, F

m_a = mass of a

m_b = mass of b

a_a = acceleration of a

a_b = acceleration of b

F = m_a × a_a = m_b × a_b

3 × m_b × a_a = m_b × a_b

3 × a_a = a_b

OR

a_a = a_b / 3

5 0
3 years ago
Calculate the force between a 0.006 C charge and a 0.001 C charge 4 meters apart.
Flauer [41]
F=\frac{9*10^9*6*10^{-3}*10^{-3}}{4^2}=\frac{54*10^3}{16}=3.375*10^3 \ N
4 0
3 years ago
A cell of e.m.f 1.5 v and internal resistance 2.5 ohm is connected in series with an ammeter of resistance 0.5 ohm and a resisto
sergejj [24]

Answer:

The current in the circuit is 0.15 Ampere

Explanation:

The given parameters of the cell are;

The electromotive force (e.m.f.) of the cell, E = 1.5 V

The resistance of the cell, r = 2.5 ohm

The resistance of the ammeter = 0.5 ohm

The resistance of the resistor = 7.0 ohm

The formula for the e.m.f., E of a cell is given as follows;

e.m.f. E = I·(R + r)

Where;

I = The current in the circuit

R = The sum of the resistances in the circuit = 7.0 Ω + 0.5 Ω + 2.5 Ω = 10 Ω

Therefore, we have;

The \ current \ in \ the \ circuit, \  I = \dfrac{E}{R + r}

Substituting the known values, gives;

I = \dfrac{1.5 \ V}{7 \ \Omega  + 0.5 \ \Omega  + 2.5 \ \Omega} = \dfrac{1.5 \ V}{10 \ \Omega} = 0.15 \ A

The current in the circuit, I = 0.15 Ampere.

6 0
3 years ago
Please help :) Thanks if you do!
Naddika [18.5K]

Answer:

moving

Explanation:

They've been moving for thousands and thousands of years. Millions of years ago there was a land called Pangea that seperated into the continents we see today.

7 0
3 years ago
Read 2 more answers
A horizontal force of 200 n is applied to move a 55-kg cart (initially at rest) across a 10-m level surface. what is the final k
Vesnalui [34]
<span>Kinetic energy is the energy that is possessed by an object that is moving. It is calculated by one-half the product of the mass and the square of the velocity of the object. We need to determine the velocity of the cart that is moving. 
</span>
First, we use Newton's Second Law of motion;
<span>Force = ma 
200 = 55a 
a = 3.64 m/s^2 

Then, from the kinematic equation we calculate the velocity;
v^2 = v0^2 + 2ax

where v is the final velocity, v0 is the initial veocity (zero since it initially start at zero), a is the acceleration ( 3.64 m/s^2) and x is the distance traveled.

v^2 = 0^2 + 2 (3.64) (10) 
v^2 = 72.73 m^2 / s^2
v = 8.53 m / s 

KE = mv^2 / 2
KE = 1/2 (55) (8.53^2) 
KE= 2000 J</span>
7 0
3 years ago
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