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koban [17]
3 years ago
7

In the velocity and acceleration are in the same direction the speed of the object decreases

Physics
1 answer:
DiKsa [7]3 years ago
7 0

Answer:

False

Explanation:

Im pretty sure the answer is false

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A woman with mass 50 kg is standing on the rim of a large disk that is rotating at 0.80 rev/s about an axis through its center.
My name is Ann [436]

Answer:

angular momentum, L=1.4\times 10^4\ kg-m^2/s

Explanation:

Given that,

Mass of the woman, m = 50 kg

Angular velocity of the disk, \omega=0.8\ rev/s=5.02\ rad/s

Mass of the disk, m' = 2670 kg

Radius of the disk, R = 4 m

We need to find the magnitude of the total angular momentum of the woman–disk system. The moment of inertia of the system is equal to the sum of moment of inertia of women and the moment off inertia of the disk.

I=mR^2+\dfrac{1}{2}m'R^2\\\\I=R^2(m+\dfrac{1}{2}m')\\\\I=(4)^2\times (50+\dfrac{1}{2}\times 270)\\\\I=2960\ kg-m^2

The angular momentum is given by :

L=I\omega\\\\L=2960\times 5.02\\\\L=14859.2\ kg-m^2/s

or

L=1.4\times 10^4\ kg-m^2/s

So, the magnitude of the total angular momentum of the woman–disk system is 1.4\times 10^4\ kg-m^2/s. Hence, this is the required solution.

7 0
3 years ago
A 40 kg shell is flying at a speed of 72 km/h. It explodes into two
viva [34]

Answer: This is true

Explanation: v2=800/25= 32m/s

5 0
3 years ago
The CEO, ellen misk, left her martian office but accidentally left a cylindricall can of coke (3.1 inches in diameter, 5.42 inch
iren2701 [21]

Answer:

Specific Gravity = 0.378

Explanation:

First, we will find the force exerted by the can on the table. This force will be equal to the weight of the can:

Pressure = Force/Area = Weight/Area

Weight = Pressure*Area

where,

Area = πdiameter²/4 = π[(3.1 in)(0.0254 m/1 in)]²/4 = 4.8 x 10⁻³ m²

Weight = (510 N/m²)(4.8 x 10⁻³ m²)

Weight = 2.48 N

Now, the weight is given as:

Weight = mg

2.48 N = m(9.8 m/s²)

m = (2.48 N)/(9.8 m/s²)

m = 0.25 kg

Now, we calculate volume of can:

Volume = (Area)(Height) = (4.8 x 10⁻³ m²)(5.42 in)(0.0254 m/1 in)

Volume = 6.6 x 10⁻⁴ m³

Hence, the density of can will be:

Density of Can = m/Volume = 0.25 kg/6.6 x 10⁻⁴ m³

Density of Can = 378.32 kg/m³

So, the specific gravity of Can will be:

Specific Gravity = Density of Can/Density of Water

Specific Gravity = (378.32 kg/m³)/(1000 kg/m³)

<u>Specific Gravity = 0.378</u>

8 0
3 years ago
Need help ASAP!!!! here are the options: Amplitude, Compression, Rarefaction, and Wavelength
Strike441 [17]
Amplitude is the pair of vertical buttons, so to speak. Compressions are the bunched up vertical lines with the purple arrows pointing left and right. Rarefactions are purple arrows pointing down. Wavelength is crest to crest purple buttons. Associated LH and RH pointing arrows.
6 0
3 years ago
Define the law of universal gravitation in your own words.
Firdavs [7]
Newton's law of universal gravitation states that a particle attracts every other particle in the universe using a force that is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers
7 0
4 years ago
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