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3 years ago

Help someone!!!I will mark you brainliest

Chemistry

2 answers:

o-na [289]3 years ago

7 0

Answer:

a) Na2S

b) AlF3

c) O2

d) C6H12O6

Explanation:

please mark me brainliest and 5 star

iVinArrow [24]3 years ago

4 0

A) Na2S
b) AlF3
c) O2
d) C6H12O6

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The length of time required for half of the radioactive atoms in a sample to decay is its. A. half-life. . B. relative date. . C

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The length of time required for half of the radioactive atoms in a sample to decay is its <span>half-life. The correct option among all the options that are given in the question is the first option or option "A". The other choices are incorrect and can be easily neglected. I hope that this is the answer that has come to your help.</span>

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3 years ago

Which best describes the data?

blondinia [14]

Answer:

The average?

Explanation:

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3 years ago

A 248-g piece of copper is dropped into 390 mL of water at 22.6 °C. The final temperature of the water was measured as 39.9 °C.

max2010maxim [7]

Answer:

The answer to your question is: Initial temperature of copper = 67.1°C

Explanation:

Data

mass Copper = 248 g

volume Water = 390 ml

T1 water = 22.6°C

T2 = 39.9°C

T1 copper = ?

Specific heat water = 1 cal/g°C

Specific heat copper = 0.092 cal/g°C

Formula copper water

Heat is negative for copper because it releases heat

- mCp(T2 - T1) = mCp(T2 - T1)

- (248)(39.9 - T1) = 390 (1)((39.9 - 22.6) Substitution

-9895.2 + 248T1 = 390(17.3) Simplification

-9895.2 + 248T1 = 6747

248 T1 = 6747 + 9895.2

248 T1 = 16642.2

T1 = 16642.2 / 248

T1 = 67.1 °C Result

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3 years ago

A 6.1-kg solid sphere, made of metal whose density is 2600 kg/m3, is suspended by a cord. When the sphere is immersed in a liqui

deff fn [24]

Answer:

Density of the liquid = 1470.43 kg/m³

Explanation:

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Mass of solid sphere(m) = 6.1 kg

Density of the metal = 2600 kg/m³

Thus volume of the liquid :

$Volume(V)=\frac{Mass(m)}{Density (\rho)}$

Volume of the sphere = 6.1 kg/2600 kg/m³ = 0.002346 m³

The volume of water displaced is equal to the volume of sphere (Archimedes' principle)

Volume displaced = 0.002346 m³

Buoyant force = $\rho\times gV$

Where

$\rho$ is the density of the fluid

g is the acceleration due to gravity

V is the volume displaced

The free body diagram of the sphere is shown in image.

According to image:

$mg=\rho\times gV+T$

Acceleration due to gravity = 9.81 ms⁻²

Tension force = 26 N

Applying in the equation to find the density of the liquid as:

$6.1\times 9.81=\rho\times 9.81\times 0.002346+26$

$33.841=\rho\times 9.81\times 0.002346$

$\rho=\frac{33.841}{9.81\times 0.002346}$

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<u>Thus, the density of the liquid = 1470.43 kg/m³</u>

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3 years ago

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option 1 is correct

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3 years ago