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kotykmax [81]
3 years ago
9

Explain what each quantum number in a quantum number set tells you about the electron. Compare and contrast the locations and pr

operties of two electrons within an atom that have the quantum number sets (3, 2, -1, +½) and (3, 1, -1, +½).
Physics
1 answer:
Allisa [31]3 years ago
3 0
There are four quantum numbers:
1) Principal quantum number which tells the shell in which the electron is and is an integer number starting from 1. Both of these electrons are in the same shell, the third.

2) Azimuthal quantum number which tells the subshell of the electron. This has a value of an integer starting from 0, 0 being the s orbital. The first electron is in the d orbital due to the number being 2 and the second is in the p orbital due to the number being 1.

3) Magnetic quantum number tells the orbital within the subshell. The first electron is in the -1 orbital of the d subshell (which has values from -2 to 2) and the second is in the -1 orbital of the p subshell (which has values from -1 to 1).

4) Spin quantum number which specifies the spin on the electron, both of the electrons have the same spin.
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A 7.00-kg object undergoes an acceleration given by ax=3.00 and ay= 9.00 m/s2. Find (a) the components of the force acting on th
lord [1]

Answer:

66.4 N

Explanation:

From Newton's second law, <em>F </em>=<em> ma</em>

where <em>F</em> is the force, <em>m</em> is the mass and <em>a</em> is the acceleration.

Because the object has acceleration in two directions and the mass is constant, the force will be in two directions. The component of the forces are:

F_x = ma_x = (7.00\text{ kg})(3.00 \text{ m/s}^2) = 21.0\text{ N}

F_y = ma_y = (7.00\text{ kg})(9.00 \text{ m/s}^2) = 63.0\text{ N}

The magnitude of the resultant force is given by

F = \sqrt{F_x^2+F_y^2}

F = \sqrt{(21.0\text{ N})^2+(63.0\text{ N})^2} = \sqrt{(441.0\text{ N}^2)+(3969.0\text{ N}^2)} = \sqrt{(4410\text{ N}^2)} = 66.4 \text{ N}

7 0
3 years ago
Read 2 more answers
An object is placed in front of a convex mirror with a radius of curvature of magnitude 10 cm. The mirror produces an image that
jek_recluse [69]

Answer:

u = - 20 cm

m =\frac{1}{5}

Given:

Radius of curvature, R = 10 cm

image distance, v = 4 cm

Solution:

Focal length of the convex mirror, f:

f = \frac{R}{2} = \frac{10}{2} = 5 cm

Using Lens' maker formula:

\frac{1}{f} = \frac{1}{u} + \frac{1}{v}

Substitute the given values in the above formula:

\frac{1}{5} = \frac{1}{u} + \frac{1}{4}

\frac{1}{u} = \frac{1}{5} - \frac{1}{4}

u = - 20 cm

where

u = object distance

Now, magnification is the ratio of image distance to the object distance:

magnification, m =\frac{|v|}{|u|}

magnification, m =\frac{|4|}{|-20|}

m =\frac{4}{20}

m =\frac{1}{5}

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3 years ago
What does it mean for a chemical equation to be balanced?
kolezko [41]

Answer:

<h2>The number of each type of atom is the same for both the reactants and products.</h2>

I hope this helps

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3 years ago
Sound waves strike a glass and cause it to shatter.
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1. Resonance. Mechanical waves act on or through a medium, these waves can often have frequencies that are synchronized in a way that makes them act on the matter in the medium more "aggressively."
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