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Helga [31]
3 years ago
7

A soccer player heads the ball and sends it flying vertically upwards at a speed of 18.0 m/s . How high above the players ' head

does the ball travel ?​
Physics
1 answer:
Darya [45]3 years ago
5 0

Answer:

<em>The ball travels up to 16.53 meters above the player's head</em>

Explanation:

<u>Vertical Launch Upwards</u>

In a vertical launch upwards, an object is launched vertically up from a height H without taking into consideration any kind of friction with the air.

If vo is the initial speed and g is the acceleration of gravity, the maximum height reached by the object is given by:

\displaystyle h_m=H+\frac{v_o^2}{2g}

The initial speed of the soccer ball is vo=18 m/s. The initial height can be assumed to be zero because we are required to find the maximum height with respect to the player's head, where the vertical motion was initiated.

Calculate the maximum height:

\displaystyle h_m=\frac{18^2}{2\cdot 9.8}

h_m=16.53\ m

The ball travels up to 16.53 meters above the player's head

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A bicyclist of mass 60kg supplies 340W of power while riding into a 5 m/s head wind. The frontal area of the cyclist and bicycle
NikAS [45]

Answer:

87.1 mph

Explanation:

We are given that

Mass,m=60 kg

Power,P=340 W

Speed,v=5 m/s

Area,A=0.344 m^2

Drag coefficient,C_d=0.88

Coefficient of rolling resistance,\mu_r=0.007

Friction force,f=\mu_rmg=0.007\times 60\times 9.8=4.1 N

Where g=9.8 m/s^2

Let speed of cyclist=v'

Drag force,F_d=\frac{1}{2}\rho_{air}AC_dv^2

Density of air,\rho_{air}=1.225 kg/m^3

F_d=\frac{1}{2}\times 1.225\times 0.344\times 0.88(5)^2=4.635N

Power,P=(F_d+f)\times v'

340=(4.1+4.635) v'=8.735v'

v'=\frac{340}{8.735}=38.9m/s

v'=87.1 mph

1 m=0.00062137 miles

1 hour=3600 s

7 0
3 years ago
Anna and Jon sit on a seesaw. Anna has a mass of 60 kg and sits 2 m from the center. Jon has a mass of 70 kg. How far from the c
Ronch [10]

Answer:

dJ = 1.7 m

Explanation:

The Equation of the Balancing the moments in the center of the seesaw  is like this:

∑Mo = 0

Mo = F*d

Where:

∑Mo : Algebraic sum of moments in the center(o) of the balance

Mo : moment in the o point ( N*m)

F  : Force ( N)

d  : distancia of the force to the the o point  ( N*m)

Data

mA = 60 kg : mass of the Anna

mJ = 70 kg :  mass of theJon

dA = 2 m : Distance from Anna to the center of the seesaw

g: acceleration due to gravity

Calculation of the distance from Jon to the center of the seesaw  (dJ)

∑Mo = 0   WA : Ana's weight   , WJ : Jon's weight

W = m*g

(WA)(dA) - (WJ) (dJ) = 0

(mA*g)(dA) - (mJ*g)(dJ) = 0

We divide by g the equation:

(mA)(dA) - (mJ)(dJ)= 0

(mA)(dA) = (mJ)(dJ)

d_{J} = \frac{m_{A} *d_{A}}{m_{J}}

d_{J} = \frac{60 kg *2 m}{70 kg}

dJ = 1.7 m

5 0
3 years ago
Read the scenario. A car travels 25 m/s forward for 10 s. Which option accurately identifies the measurements within the scenari
Phantasy [73]

Explanation:

It is given that,

A car travels 25 m/s forward for 10 s.

Solution,

For a vector, a quantity must have both magnitude as well as the direction. For a scalar, a quantity have only the magnitude. In this case, the car moves in forward direction.  This is the only difference between the vector and the scalar.

Out of given option,s the correct option is (c) "The measurement 25 m/s is the only vector quantity because it is a measurement of speed".

5 0
3 years ago
Diffusion and osmosis are forms of passive transport.<br><br> True<br> False
pishuonlain [190]

Answer:

True. Diffusion and osmosis are forms of passive transport.

Explanation:

In diffusion, particles move from an area of higher concentration to one of lower concentration until equilibrium is reached.

In osmosis, a semipermeable membrane is present, so only the solvent molecules are free to move to equalize concentration.

8 0
3 years ago
Read 2 more answers
A spaceship from a friendly, extragalactic planet flies toward Earth at 0.203 0.203 times the speed of light and shines a powerf
Serjik [45]

Answer:

567.321nm

Explanation:

See attached handwritten document for more details

7 0
3 years ago
Read 2 more answers
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