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ZanzabumX [31]
4 years ago
7

Where Are You Going ? Select the statement that describes the speed and velocity of two tennis players when one walks away to th

e southwest and the other to the northeast , with both walking at the same pace
Physics
1 answer:
ss7ja [257]4 years ago
5 0

Answer:

Speed: a tennis player moving at 3 m/s

Velocity: a tennis player moving at 3 m/s in the northeast direction

Explanation:

Here the statements are not given, however we can explain the difference between speed and velocity and give two examples.

  • Speed is a scalar quantity which tells how fast an object is moving, regardless of its direction. It is calculated as distance covered divided by time taken.
  • Velocity is a vector quantity, which has a magnitude and a direction. The magnitude is the ratio between the displacement (a vector connecting the initial position to the final position) and the time taken, while the direction goes from the initial position to the final position.

Therefore, examples of speed and velocity are:

Speed: a tennis player moving at 3 m/s

Velocity: a tennis player moving at 3 m/s in the northeast direction (for velocity, direction must also be specified)

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6 0
3 years ago
A claw hammer is used to pull a nail from a piece of wood. Where should you place your hand on the handle and where should the n
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4 0
4 years ago
A two-turn circular wire loop of radius 0.63 m lies in a plane perpendicular to a uniform magnetic field of magnitude 0.219 T. I
Basile [38]

Answer:

The magnitude of the average induced emf in the wire during this time is 9.533 V.

Explanation:

Given that,

Radius r= 0.63 m

Magnetic field B= 0.219 T

Time t= 0.0572 s

We need to calculate the average induce emf in the wire during this time

Using formula of induce emf

E=-\dfrac{d\phi}{dt}

E=-B\dfrac{dA}{dt}

E=-B\dfrac{A_{2}-A_{1}}{dt}

E=B\dfrac{A_{1}-A_{2}}{dt}.....(I)

In reshaping of wire, circumstance must remain same.

We calculate the length when wire is in two loops

l=2\times 2\pi\times r_{1}

l=2\times 2\pi\times 0.63

l=7.916\ m

The length when wire is in one loop

l=2\pi\times r_{2}

7.916=2\times \pi\times r_{2}

r_{2}=\dfrac{7.916}{2\times \pi}

r_{2}=1.259\ m

We need to calculate the initial area

A_{1}=N\times\pi\times r_{1}^2

Put the value into the formula

A_{1}=2\times3.14\times(0.63)^2

A_{1}=2.49\ m^2

The final area is

A_{2}=N\times\pi\times r_{2}^2

A_{2}=1\times\pi\times(1.259)^2

A_{2}=4.98\ m^2

Put the value of initial area and final area in the equation (I)

E=0.219\dfrac{2.49-4.98}{0.0572}

E=-9.533\ V

Negative sign shows the direction of induced emf.

Hence, The magnitude of the average induced emf in the wire during this time is 9.533 V.

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A thin film of MgF₂ (n = 1.38) coats a piece of glass. Constructive interference is observed for the reflection of light with wa
TEA [102]

Answer:

t = 905.8 nm

Explanation:

Given:

- Wavelength λ_1 = 500 nm

- Wavelength λ_2 = 625 nm

- MgF₂ refractive index n = 1.38

Find:

What is the thinnest film for which this can occur?

Solution:

- We have two different wavelength of light that constructively interfere at the surface of the film. We need the minimum thickness of film that would satisfy the condition of constructive interference for both!

-Since the refractive index of glass is greater than that of MgF_2, the expression of constructive interference would be as follows:

                                2*t = m*λ / n

- Since, the orders m are unknown for each wavelength, also different. We will try to determine the first for each wavelength of light.

- Construct two equation:

                                t = m_1*(500 nm ) / (2*1.38 )

                                t = 181.1594203*m_1  nm

                                t = m_2*(625 nm ) / (2*1.38 )

                                t = 226.4492754*m_2  nm

- Now equate the two thicknesses which should be equal:

                               226.4492754*m_2 = 181.1594203*m_1

                               m_2 = 0.8*m_1

- Now we know that m can only take integer values, and m is proportional to thickness t. So for thinnest thickness m's must take the least integer values. Hence, we have:                    

                               m_2 = (4 / 5) * m_1

So,                           m_1 = 5 , m_2 = 4   ..... Least integer values.

- Now that we have m's we can compute the thickness t as follows:

                                t = 181.1594203*m_1  nm

- Substitute m_1 = 5, we have:

                                t = 181.1594203*5  nm

                               t = 905.8 nm

- Substitute m_2 = 4 in:

                                 t = 226.4492754*m_2

                                 t = 226.4492754*4

                                t = 905.8 nm

- Our values of t = 905.8 nm matches for both wavelengths.

                                   

7 0
4 years ago
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