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const2013 [10]
3 years ago
9

Please help me with this...And Show all steps correctly​

Physics
1 answer:
ipn [44]3 years ago
4 0

Answer:

4 m

Explanation:

From the question given above, the following data were obtained:

Initial velocity (u) = 10 m/s

Acceleration (a) = –8m/s²

Time (t) = 2 s

Displacement (s) =?

The displacement of the object can be obtained as follow:

s = ut + ½at²

s = (10 × 2) + (½ × –8 × 2²)

s = 20 + (–4 × 4)

s = 20 + (–16)

s = 20 – 16

s = 4 m

Thus, the displacement of the object is 4 m.

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Monochromatic light falling on two very narrow slits 0.048mm apart. Successive fringes on a screen 5.00m away are 6.5cm apart ne
tino4ka555 [31]

Answer:

λ = 5.85 x 10⁻⁷ m = 585 nm

f = 5.13 x 10¹⁴ Hz

Explanation:

We will use Young's Double Slit Experiment's Formula here:

Y = \frac{\lambda L}{d}\\\\\lambda = \frac{Yd}{L}

where,

λ = wavelength = ?

Y = Fringe Spacing = 6.5 cm = 0.065 m

d = slit separation = 0.048 mm = 4.8 x 10⁻⁵ m

L = screen distance = 5 m

Therefore,

\lambda = \frac{(0.065\ m)(4.8\ x\ 10^{-5}\ m)}{5\ m}

<u>λ = 5.85 x 10⁻⁷ m = 585 nm</u>

Now, the frequency can be given as:

f = \frac{c}{\lambda}

where,

f = frequency = ?

c = speed of light = 3 x 10⁸ m/s

Therefore,

f = \frac{3\ x\ 10^8\ m/s}{5.85\ x\ 10^{-7}\ m}\\\\

<u>f = 5.13 x 10¹⁴ Hz</u>

5 0
2 years ago
The density of an object is dependent upon the object’s mass and ---
kotegsom [21]

Answer:Volume

Explanation:

Density = mass/ Volume

7 0
3 years ago
At what speed must a 0.6 kg stone be thrown in order that it has a relativistic mass of 0.76 kg? (c = 3.00 x 10^8 m/s) (A) 0.39
exis [7]

Explanation:

It is given that,

Relativistic Mass of the stone, m₀ = 0.6

Mass, m=0.76\ kg

Relativistic mass is given by :

m=\dfrac{m_o}{\sqrt{1-\dfrac{v^2}{c^2}}}.........(1)

Where

c is the speed of light

On rearranging equation (1) we get :

v^2=c^2(1-(\dfrac{m_o}{m})^2)

v=c\sqrt{ (1-(\dfrac{m_o}{m})^2)}

v=c\sqrt{ (1-(\dfrac{0.6}{0.76})^2)}

v = 0.61378 c

or

v = 0.6138 c

So, the correct option is (c). Hence, this is the required solution.

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2 years ago
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A and C, The Color and Texture of the material. 
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2 years ago
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The Kapandu boys dormitory in the UPNG is going up in flames. Rachel, a former student of Physics, who
Tom [10]

Answer:

<em>1108.464 N of force</em>

Explanation:

diameter of water hose = 70 cm = 0.7 m

radius = 0.7/2 = 0.35 m

volumetric flow rate Q = 420 L/min

1 L = 0.001 m^3

1 min = 60 s

therefore,

Q = 420 L/min = (420 x 0.001)/60 = 0.007 m^3/s

Area A of fire hose = πr^{2} = 3.142 x 0.35^{2} = 0.38 m^2

<em>From continuity equation, Q = AV</em>

where V1 is the velocity of the water through the pipe, and A1 is the area of the pipe.

Q = A1V1

0.007 = 0.38V1

V1 = 0.007/0.38 = 0.018 m/s.

Nozzle diameter = 0.75 cm = 0.0075 m

radius = 0.00375

Area = πr^{2} = 3.142 x 0.00375^{2} = 4.42 x 10^{-5} m^2

velocity of water through the nozzle will be

V2 = Q/A2 = 0.007 ÷ (4.42 x 10^{-5}) = 158.37 m/s

From

<em>F = ρQ(v2 - v1)</em>

Where,

F = force exerted

p = density of water = 1000 kg/m^3

F = 1000 x 0.007 x (158.37 - 0.018) = <em>1108.464 N of force</em>

4 0
3 years ago
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