Calculate the specific heat (J/g∘C) for a 18.5-g sample of tin that absorbs 183 J when temperature increases from 35.0 ∘C to 78.
2 answers:
Answer:
0.227 J/g°C
Explanation:
Specific heat is the heat change by one gram of substance if it is subjected to change of 1 degree celsius.
The relation between specific heat and mass and change in temperature is:
Q = heat change = mass X specific heat X change in temperature.
Given:
Q = 183 J
Mass = 18.5g
increase in temperature = 78.6-35 = 43.6 °C
Putting values
183 = 18.5X specific heat X 43.6
Specific heat =
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