Calculate the specific heat (J/g∘C) for a 18.5-g sample of tin that absorbs 183 J when temperature increases from 35.0 ∘C to 78.
2 answers:
Answer:
0.227 J/g°C
Explanation:
Specific heat is the heat change by one gram of substance if it is subjected to change of 1 degree celsius.
The relation between specific heat and mass and change in temperature is:
Q = heat change = mass X specific heat X change in temperature.
Given:
Q = 183 J
Mass = 18.5g
increase in temperature = 78.6-35 = 43.6 °C
Putting values
183 = 18.5X specific heat X 43.6
Specific heat =
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Let the three equations with given be denoted as (1), (2), (3), and the last equation (4). Let
,
, and
be letters such that
. This relationship shall hold for all chemicals involved.
There are three unknowns; it would thus take at least three equations to find their values. Species present on both sides of the equation would cancel out. Thus, let coefficients on the reactant side be positive and those on the product side be negative, such that duplicates would cancel out arithmetically. For instance, shall resemble the number of
left on the product side when the second equation is directly added to the third. Similarly
:
:
:
Thus
and
Verify this conclusion against a fourth species involved- for instance. Nitrogen isn't present in the net equation. The sum of its coefficient shall, therefore, be zero.
Apply the Hess's Law based on the coefficients to find the enthalpy change of the last equation.