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3 years ago

Find the Slope Ayo help me please

Mathematics

1 answer:

Lubov Fominskaja [6]3 years ago

4 0

-1/8

4-2/-3/4 - - 1/2
Two negatives make a positive so,
4-2/-3/4 + 1/2 = 2/ -3/4 +2/4 =
2/ -1/4 , to divide a fraction you have to
Keep Change Flip
So,
-1/4 x 1/2 = -1/8

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X-7=5 please help me with each step.

KATRIN_1 [288]

x-7=5

Move -7 to the other side. Sign changes from -7 to +7.

x-7+7=5+7

x=5+7

x=12

Answer: x=12

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3 years ago

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What problem led to playgrounds becoming more common in America cities

son4ous [18]

This link might help you :)

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3 years ago

3x+4(x-8)-14 evaluate for x=11

djverab [1.8K]

Answer:

For X = 11, the expression is equal to 31

Step-by-step explanation:

Hello

For X = 11 you only have to replaced the value into the expression, so:

3(11) + 4(11-8) - 14

33 + 4(3) - 14

33 + 12 - 14

Best regards

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3 years ago

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Naval intelligence reports that 4 enemy vessels in a fleet of 17 are carrying nuclear weapons. If 9 vessels are randomly targete

icang [17]

Answer:

0.7588 = 75.88% probability that more than 1 vessel transporting nuclear weapons was destroyed

Step-by-step explanation:

The vessels are destroyed without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

In this question:

Fleet of 17 means that $N = 17$

4 are carrying nucleas weapons, which means that $k = 4$

9 are destroyed, which means that $n = 9$

What is the probability that more than 1 vessel transporting nuclear weapons was destroyed?

This is:

$P(X > 1) = 1 - P(X \leq 1)$

In which

$P(X \leq 1) = P(X = 0) + P(X = 1)$

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

$P(X = 0) = h(0,17,9,4) = \frac{C_{4,0}*C_{13,9}}{C_{17,9}} = 0.0294$

$P(X = 1) = h(1,17,9,4) = \frac{C_{4,1}*C_{13,8}}{C_{17,9}} = 0.2118$

Then

$P(X \leq 1) = P(X = 0) + P(X = 1) = 0.0294 + 0.2118 = 0.2412$

$P(X > 1) = 1 - P(X \leq 1) = 1 - 0.2412 = 0.7588$

0.7588 = 75.88% probability that more than 1 vessel transporting nuclear weapons was destroyed

8 0

2 years ago

If a=3/6 and b=-3/-5 find -3a+4b

Fiesta28 [93]

Answer:

Step-by-step explanation:

-3(3/6) + 4(3/5)

-3(1/2) + 4(3/5)

-3/2 + 12/5

-15/10 + 24/10

9/10

7 0

3 years ago