Answer:
F = 0i (in the x-direction), 0j (in the y-direction),-8.59*10^-4 N k (In the z-direction)
Explanation:
The force given by charged particles moving in a magnetic field is given below (cross is cross product, they don't have that format in the equation tool):

Now we can perform the cross product between v and B
d{array}\right][/tex]
Now multiply by Q (charge) to get the force

F = -8.59*10^-4 N k
F = 0i, 0j, (-8.59*10^-4)k
Given :
Mass of box , m = 250 kg.
Force applied , F = 285 N.
The value of the incline angle is 30°.
the coefficient of dynamic friction is
.
To Find :
The speed with which the box is moving with, assuming it takes 4 seconds to reach the top of the incline.
Solution :
Net force applied in box is :

Acceleration ,
.
By equation of motion :

Therefore, the speed of box is 12.04 m/s.
Hence, this is the required solution.
Answer:
The first is that the object moves
density equals mass over volume for example: d=m/v, so 45.837g/1703.3414cm =
p = 0.02691 g/cm3
=11.943cm
You would have to do some conversion to get the 11.943cm
Answer:
D
Explanation:
Beacuse the force got to the bottem first Meaning the andswer is D