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Novay_Z [31]
3 years ago
6

A beam of monochromatic light (f =5.09 ×1014 Hz) has a wavelength of 589 nanometers in air. What is the wavelength of this light

in Lucite?
(1)150 nm
(2)393 nm
(3)589 nm
(4)884 nm
Physics
1 answer:
frosja888 [35]3 years ago
7 0
Lucite has a refractive index of n=1.50. This means that the speed of the light in lucite is decreased according to:
v=\frac{c}{n}
where c=3 \cdot 10^8 m/s is the speed of light in air. Putting the number in the formula, we find that the speed of light in lucite is
v=\frac{3 \cdot 10^8 m/s}{1.50}=2\cdot 10^8 m/s
The frequency of the light is f=5.09 \cdot 10^{14}Hz, so now we can calculate the wavelength in lucite by using the formula:
\lambda=\frac{v}{f}=\frac{2\cdot 10^8 m/s}{5.09 \cdot 10^{14} Hz}=3.93 \cdot 10^{-7} m=393 nm
<span>Therefore, the correct answer is (2) 393 nm.</span>
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Answer:

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Explanation:

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F=qv (cross) B\\

Now we can perform the cross product between v and B

v(cross)B = \left[\begin{array}{cc}4.19*10^{4} &-3.85*10^{4}\\1.8&0&\en[tex]v(cross)B = 69300 (kg*m/(s^2*C))\\d{array}\right][/tex]

Now multiply by Q (charge) to get the force

F = -1.24*10^-8 * 69300\\F = -8.59*10^-4N

F = -8.59*10^-4 N k

F = 0i, 0j, (-8.59*10^-4)k

6 0
3 years ago
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docker41 [41]

Given :

Mass of box , m = 250 kg.

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Solution :

Net force applied in box is :

F=285 - mgsin\ \theta - \mu mg cos \ \theta\\ \\F=285-mg( sin \ \theta - \mu cos\ \theta)\\\\F=285 - 20\times 10( \dfrac{1}{2}+0.72\times \dfrac{\sqrt{3}}{2})\\\\F=60.29\ N

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By equation of motion :

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3 years ago
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Wewaii [24]

Answer:

The first is that the object moves

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3 years ago
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Finger [1]

density equals mass over volume for example: d=m/v, so 45.837g/1703.3414cm =

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8 0
4 years ago
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Answer:

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