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3 years ago

Explain what a convection current is? who ever sees this I hope you have a wonderful day!

Chemistry

1 answer:

Alika [10]3 years ago

3 0

Answer:

Convection currents are flowing fluid that is moving because there is a temperature or density difference within the material.

Because particles within a solid are fixed in place, convection currents are seen only in gases and liquids. A temperature difference leads to an energy transfer from an area of higher energy to one of lower energy.

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Compare/Contrast Make a song, poem, journal, story, etc comparing and contrasting metals, nonmetals, and metalloids. Be sure to

likoan [24]

Answer:

here you go

Explanation:

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3 years ago

Dolphins communicate using compression waves (longitudinal waves). Some of the sounds dolphins make are outside the range of hum

Alchen [17]

Question 4 is A. longitudinal waves

8 0

3 years ago

In addition to mass balance, oxidation-reduction reactions must be balanced such that the number of electrons lost in the oxidat

Fiesta28 [93]

Answer:

Part A: (1, 1, 4, 1, 1, 1)

Part B: (2, 6, 4, 2, 3, 8)

Explanation:

Redox reactions can be balanced using the half-reaction method. It has the following steps:

We write both half-reactions (reduction and oxidation)
We balance the masses using H⁺ and H₂O in acidic media or OH⁻ and H₂O in basic media.
We add electrons to balance electrically the half-reaction
We multiply the half-reaction by numbers to make sure the number of electrons gained and lost are the same.
We add both half-reactions and take the numbers to the general equation.

Acidic solution

SO₄²⁻(aq) + Sn²⁺(aq) + X ⇄ H₂SO₃(aq) + Sn⁴⁺(aq) + Y

Reduction: SO₄²⁻ ⇒ SO₃²⁻

Oxidation: Sn²⁺ ⇒ Sn⁴⁺

2 H⁺ + SO₄²⁻ ⇒ SO₃²⁻ + H₂O

Sn²⁺ ⇒ Sn⁴⁺

2 H⁺ + SO₄²⁻ + 2 e⁻ ⇒ SO₃²⁻ + H₂O

Sn²⁺ ⇒ Sn⁴⁺ + 2 e⁻

1 x [2 H⁺ + SO₄²⁻ + 2 e⁻ ⇒ SO₃²⁻ + H₂O]

1 x [Sn²⁺ ⇒ Sn⁴⁺ + 2 e⁻]

2 H⁺ + SO₄²⁻ + 2 e⁻ + Sn²⁺ ⇄ SO₃²⁻ + H₂O + Sn⁴⁺ + 2 e⁻

2 H⁺ + SO₄²⁻ + Sn²⁺ ⇄ SO₃²⁻ + H₂O + Sn⁴⁺

Taking this to the general equation:

SO₄²⁻(aq) + Sn²⁺(aq) + 2 H⁺(aq) ⇄ H₂SO₃(aq) + Sn⁴⁺(aq) + H₂O(l)

Since H⁺ are spectator ions, they are not balanced automatically through this method and we have to balance them manually. In this case, we need to add 2 more H⁺ to the left.

SO₄²⁻(aq) + Sn²⁺(aq) + 4 H⁺(aq) ⇄ H₂SO₃(aq) + Sn⁴⁺(aq) + H₂O(l)

Basic solution

MnO₄⁻(aq) + F⁻(aq) + X ⇄ MnO₂(s) + F₂(aq) + Y

Reduction: MnO₄⁻ ⇒ MnO₂

Oxidation: F⁻ ⇒ F₂

2 H₂O + MnO₄⁻ ⇒ MnO₂ + 4 OH⁻

2 F⁻ ⇒ F₂

2 H₂O + MnO₄⁻ + 3 e⁻ ⇒ MnO₂ + 4 OH⁻

2 F⁻ ⇒ F₂ + 2 e⁻

2 × (2 H₂O + MnO₄⁻ + 3 e⁻ ⇒ MnO₂ + 4 OH⁻)

3 × (2 F⁻ ⇒ F₂ + 2 e⁻)

4 H₂O + 2 MnO₄⁻ + 6 e⁻ + 6 F⁻ ⇄ 2 MnO₂ + 8 OH⁻ + 3 F₂ + 6 e⁻

4 H₂O + 2 MnO₄⁻ + 6 F⁻ ⇄ 2 MnO₂ + 8 OH⁻ + 3 F₂

Taking this to the general equation:

2 MnO₄⁻(aq) + 6 F⁻(aq) + 4 H₂O ⇄ 2 MnO₂(s) + 3 F₂(aq) + 8 OH⁻

This equation is balanced.

6 0

3 years ago

A solution with a pOH of 6.92 has an [OH−] concentration of____

o-na [289]

Answer:

It is: 1.2x10⁻⁷

8 0

3 years ago

BRAINLIESTT ASAP! PLEASE HELP :)

nexus9112 [7]

Explanation:

First two pictures go together

From top to bottom, ionisation energy decreases [electron shielding], while from left to right, ionisation energy increases [valence shell stability]. Noble gases always always possess such high energy of ionisation because they are stable, with Helium having the highest ionisation of all elements.

From top to bottom, electron affinity decreases [decrease in atomic radius], while from left to right, electron affinity increases [increase in atomic radius].

There are many more trends, but I have ran out of space, so I will put this in the comments.

I am joyous to assist you anytime.

6 0

3 years ago