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MArishka [77]
3 years ago
11

Explain what a convection current is? who ever sees this I hope you have a wonderful day!

Chemistry
1 answer:
Alika [10]3 years ago
3 0

Answer:

Convection currents are flowing fluid that is moving because there is a temperature or density difference within the material.

Because particles within a solid are fixed in place, convection currents are seen only in gases and liquids. A temperature difference leads to an energy transfer from an area of higher energy to one of lower energy.

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Answer:

here you go

Explanation:

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Dolphins communicate using compression waves (longitudinal waves). Some of the sounds dolphins make are outside the range of hum
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Question 4 is <span>A. longitudinal waves </span>
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In addition to mass balance, oxidation-reduction reactions must be balanced such that the number of electrons lost in the oxidat
Fiesta28 [93]

Answer:

Part A: (1, 1, 4, 1, 1, 1)

Part B: (2, 6, 4, 2, 3, 8)

Explanation:

Redox reactions can be balanced using the half-reaction method. It has the following steps:

  1. We write both half-reactions (reduction and oxidation)
  2. We balance the masses using H⁺ and H₂O in acidic media or OH⁻ and H₂O in basic media.
  3. We add electrons to balance electrically the half-reaction
  4. We multiply the half-reaction by numbers to make sure the number of electrons gained and lost are the same.
  5. We add both half-reactions and take the numbers to the general equation.

<em>Acidic solution</em>

SO₄²⁻(aq) + Sn²⁺(aq) + X ⇄ H₂SO₃(aq) + Sn⁴⁺(aq) + Y

1.

Reduction: SO₄²⁻ ⇒ SO₃²⁻

Oxidation: Sn²⁺ ⇒ Sn⁴⁺

2.

2 H⁺ + SO₄²⁻ ⇒ SO₃²⁻ + H₂O

Sn²⁺ ⇒ Sn⁴⁺

3.

2 H⁺ + SO₄²⁻ + 2 e⁻ ⇒ SO₃²⁻ + H₂O

Sn²⁺ ⇒ Sn⁴⁺ + 2 e⁻

4.

1 x [2 H⁺ + SO₄²⁻ + 2 e⁻ ⇒ SO₃²⁻ + H₂O]

1 x [Sn²⁺ ⇒ Sn⁴⁺ + 2 e⁻]

5.

2 H⁺ + SO₄²⁻ + 2 e⁻ + Sn²⁺ ⇄ SO₃²⁻ + H₂O + Sn⁴⁺ + 2 e⁻

2 H⁺ + SO₄²⁻ + Sn²⁺ ⇄ SO₃²⁻ + H₂O + Sn⁴⁺

Taking this to the general equation:

SO₄²⁻(aq) + Sn²⁺(aq) + 2 H⁺(aq) ⇄ H₂SO₃(aq) + Sn⁴⁺(aq) + H₂O(l)

Since H⁺ are spectator ions, they are not balanced automatically through this method and we have to balance them manually. In this case, we need to add 2 more H⁺ to the left.

SO₄²⁻(aq) + Sn²⁺(aq) + 4 H⁺(aq) ⇄ H₂SO₃(aq) + Sn⁴⁺(aq) + H₂O(l)

<em>Basic solution</em>

MnO₄⁻(aq) + F⁻(aq) + X ⇄ MnO₂(s) + F₂(aq) + Y

1.

Reduction: MnO₄⁻ ⇒ MnO₂

Oxidation: F⁻ ⇒ F₂

2.

2 H₂O + MnO₄⁻ ⇒ MnO₂ + 4 OH⁻

2 F⁻ ⇒ F₂

3.

2 H₂O + MnO₄⁻ + 3 e⁻ ⇒ MnO₂ + 4 OH⁻

2 F⁻ ⇒ F₂ + 2 e⁻

4.

2 × (2 H₂O + MnO₄⁻ + 3 e⁻ ⇒ MnO₂ + 4 OH⁻)

3 × (2 F⁻ ⇒ F₂ + 2 e⁻)

5.

4 H₂O + 2 MnO₄⁻ + 6 e⁻ + 6 F⁻ ⇄ 2 MnO₂ + 8 OH⁻ + 3 F₂ + 6 e⁻

4 H₂O + 2 MnO₄⁻ + 6 F⁻ ⇄ 2 MnO₂ + 8 OH⁻ + 3 F₂

Taking this to the general equation:

2 MnO₄⁻(aq) + 6 F⁻(aq) + 4 H₂O ⇄ 2 MnO₂(s) + 3 F₂(aq) + 8 OH⁻

This equation is balanced.

6 0
3 years ago
A solution with a pOH of 6.92 has an [OH−] concentration of____
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Answer:

It is: 1.2x10⁻⁷

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3 years ago
BRAINLIESTT ASAP! PLEASE HELP :)
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Explanation:

<em>First</em><em> </em><em>two</em><em> </em><em>pictures</em><em> </em><em>go</em><em> </em><em>together</em>

From top to bottom, <em>ionisation energy</em> <em>decreases</em><em> </em>[electron shielding], while from left to right, ionisation energy <em>increases</em><em> </em>[valence shell stability]. Noble gases always always possess such high energy of ionisation because they are stable, with Helium having the highest ionisation of all elements.

From top to bottom, <em>electron affinity</em> <em>decreases</em> [decrease in atomic radius], while from left to right, electron affinity <em>increases</em><em> </em>[increase in atomic radius].

There are many more trends, but I have ran out of space, so I will put this in the comments.

I am joyous to assist you anytime.

6 0
3 years ago
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