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zysi [14]
3 years ago
5

A double-slit experiment is performed with light of wavelength 620 nm. The bright interference fringes are spaced 2.3 mm apart o

n the viewing screen. What will the fringe spacing be if the light is changed to a wavelength of 360 nm?
Physics
1 answer:
tia_tia [17]3 years ago
5 0

Answer:

1.34 mm

Explanation:

A double slit experiment is conducted with a light which has a wavelength of 620 nm

The fringes are separated 2.3 mm apart

The light is changed to a wavelength length of 360 nm

Let x represent the fringe spacing as a result of the change in wavelength

Therefore,the fringe spacing can be calculated as follows

2.3mm/x= 620nm/360nm

Multiply both sides

x × 620= 2.3×360

620x= 828

x= 828/620

x= 1.34 mm

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Answer:

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             x_total = (A + B) cos (wt + Ф)

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