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Romashka [77]
3 years ago
12

Three objects -- two of mass m and one of mass m -- are located at three corners of a square of edge length ℓ. find the gravitat

ional field g at the fourth corner due to these objects. (express your answers in terms of the edge length ℓ, the masses m and m, and the gravitational constant g). magnitude
Physics
1 answer:
Debora [2.8K]3 years ago
5 0
The magnitude of the gravitational field is = GM/R^2Where:R = l, and G = gravitation constant, m = mass 

The field strength of the diagonal mass is computed by GM/(l*√2)^2 
And the sum of the field magnitudes from the two neighbored masses is GM*√2/l^2. 

So the total magnitude is computed by: GM/(2l^2) + GM√(2)/l^2 
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The human eye can change the shape of its crystalline lens, and thus modify the lens strength (a.k.a., lens power) of the eye in
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2 years ago
Did the bigbang violate the law of conservation of energy and matter?
Pie
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3 0
3 years ago
flat sheet is in the shape of a rectangle with sides of lengths 0.400 mm and 0.600 mm. The sheet is immersed in a uniform electr
Ksenya-84 [330]

Answer:

6.29591\times 10^{-6}\ N/C^2

Explanation:

Flux is given by

\phi=EAcos\theta

A = Area

A=0.4\times 10^{-3}\times 0.6\times 10^{-3}

E = Electric field = 76.7 N/C

Angle is given by

\theta=90-20\\\Rightarrow \theta=70^{\circ}

\phi=76.7\times 0.4\times 10^{-3}\times 0.6\times 10^{-3}\times cos70\\\Rightarrow \phi=6.29591\times 10^{-6}\ N/C^2

The flux through the sheet is 6.29591\times 10^{-6}\ N/C^2

6 0
2 years ago
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