Question

Gastric acid pH can range from 1 to 4, and most of the acid is HCl.

Answer 1

Given the molarity of the solution is$3.03*10^{-2}$.

The volume of the solution is 10.9/1000 L

Number of moles of HCl = Molarity * volume of the solution in L

Number of moles of HCl =$3.03*10^{-2}$*$\frac{1000}{10.9}$

Number of moles of HCl = 2.7 moles.

Therefore number of moles of HCl in 10.9 ml of the stomach acid is 2.7 moles