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Elina [12.6K]
3 years ago
9

The width, in meters, of a rectangle is 3 more than twice its length. The area is 35 square meters. What type of function would

best be used to find the length of the rectangle?

Mathematics
1 answer:
anzhelika [568]3 years ago
3 0

Answer:

Quadratic

Step-by-step explanation:

Area of rectangle: width x length

assume length is x meter

Area= x(x+3)=35

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Angle θ between two vectors is given by, \theta =cos^{-1}( \frac{u&#10; \cdot v}{|u||v|} ); where u \cdot &#10;v=-5(-4)+(-4)(-3)=20+12=32; |u|= \sqrt{ (-5)^{2} + (-4)^{2} } = &#10;\sqrt{25+16} = \sqrt{41} and |v|=\sqrt{ (-4)^{2} + (-3)^{2} } = &#10;\sqrt{16+9} = \sqrt{25}=5.
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