A. The maximum possible mass of sodium that can be produced is 47.18 Kg
B. The percentage yield of the reaction is 80.6%
<h3>Determination of the mass of NaCl and Na </h3>
We'll begin by calculating the mass of NaCl that reacted and the mass of Na obtained from the balanced equation.
2NaCl –> 2Na + Cl₂
Molar mass NaCl = 23 + 35.5 = 58.5 g/mol
Mass of NaCl from the balanced equation = 2 × 58.5 = 117 g = 117 / 1000 = 0.117 Kg
Molar mass of Na = 23 g/mol
Mass of Na from the balanced equation = 2 × 23 = 46 g = 46 / 1000 = 0.046 Kg
SUMMARY
From the balanced equation above,
0.117 Kg of NaCl reacted to produce 0.046 Kg of Na.
<h3>A. How to determine mass of Na produced </h3>
From the balanced equation above,
0.117 Kg of NaCl reacted to produce 0.046 Kg of Na.
Therefore,
120 Kg of NaCl will react to produce = (120 × 0.046) / 0.117 = 47.18 Kg of Na
Thus, the maximum mass of Na produced is 47.18 Kg.
<h3>B. How to determine the percentage yield </h3>
- Actual yield = 38.05 Kg
- Theoretical yield = 47.18 Kg
Percentage yield = (Actual / Theoretical) × 100
Percentage yield = (38.05 / 47.18) × 100
Percentage yield = 80.6%
Learn more about stoichiometry:
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