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den301095 [7]
3 years ago
13

A soccer ball is dropped from the height of 2m and falls to the floor. What is the relationship of the potential and kinetic ene

rgies of the ball as the ball falls to the floor?
Physics
1 answer:
Alexandra [31]3 years ago
4 0

We know , gravitational force is a conservative force .

Therefore , total energy of the system remains constant .

P.E_i+K.E_i=P.E_f+K.E_f

Let , mass of object is m.

So ,

mg(2)+0=0+\dfrac{mv_f^2}{2}\\\\v_f=\sqrt{4g}\\\\v_f=\sqrt{4\times 9.8}\ m/s\\\\v_f=6.26\ m/s

Therefore , the velocity at floor is 6.26 m/s .

Hence , this is the required solution .

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8 0
3 years ago
If f(x)=4/x+2 and g is the inverse of f,then g'(10)=​
ch4aika [34]

Answer:

g'(10) = \frac{-1}{16}

Explanation:

Since g is the inverse of f ,

We can write

g(f(x)) = x    <em> </em><em>(Identity)</em>

Differentiating both sides of the equation we get,

g'(f(x)).f'(x) = 1

g'(10) = \frac{1}{f'(x)}    --equation[1]    Where f(x) = 10

Now, we have to find x when f(x) = 10

Thus 10 = \frac{4}{x} + 2

\frac{4}{x} = 8

x = \frac{1}{2}

Since f(x) = \frac{4}{x} + 2

f'(x) = -\frac{4}{x^{2} }

f'(\frac{1}{2})  =  -4 × 4 = -16            

Putting it in equation 1, we get:

We get g'(10) = -\frac{1}{16}

5 0
3 years ago
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