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den301095 [7]
3 years ago
13

A soccer ball is dropped from the height of 2m and falls to the floor. What is the relationship of the potential and kinetic ene

rgies of the ball as the ball falls to the floor?
Physics
1 answer:
Alexandra [31]3 years ago
4 0

We know , gravitational force is a conservative force .

Therefore , total energy of the system remains constant .

P.E_i+K.E_i=P.E_f+K.E_f

Let , mass of object is m.

So ,

mg(2)+0=0+\dfrac{mv_f^2}{2}\\\\v_f=\sqrt{4g}\\\\v_f=\sqrt{4\times 9.8}\ m/s\\\\v_f=6.26\ m/s

Therefore , the velocity at floor is 6.26 m/s .

Hence , this is the required solution .

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SpyIntel [72]
Well if you take 10 minutes to walk each mile and you don't stop by continuously walking... it would take approximately 69 and a half daysSource(s):<span>10 minutes x 10,000 miles= 100,000 minutes 
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6 0
3 years ago
Which of the following is true for a parallel circuit?
svet-max [94.6K]

Answer:

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3 0
2 years ago
Children are sled riding on a hill One little girl pulls her sled back up the hill and does 379.5 joules of work while pulling i
Serggg [28]

Answer:

2.2N

Explanation:

Given parameters:

Work done  = 379.5J

Height  = 173m

Unknown:

Amount of force exerted on the sled  = ?

Solution:

The amount of force she exerted on the sled is the same as her weight.

Work done is the force applied to move a body through a distance.

      Work done  = mgh

m is the mass

g is the acceleration due to gravity

h is the height

     mg  = weight;

        Work done  = weight x h

           379.5 = weight  x  173

           weight  = \frac{379.5}{173}   = 2.2N

4 0
2 years ago
In which of the following situation is light most likely to be a reflection
maxonik [38]

Answer:

when the reflecting surface is plain and without even small hurdles that are not the visible by our naked eyes. Eg : plain mirror

Explanation:

7 0
3 years ago
An Iowa class warship holds the record for the fastest warship. If the ship accelerates uniformly from rest at 0.15 m/s² for 2 m
Mumz [18]
The equation to be used is the derived formulas for rectilinear motion at a constant acceleration. The formula for acceleration is

a = (v - v₀)/t
where
v and v₀ are the initial and final velocities, respectively
t is the time
a is the acceleration

Since it started from rest, v₀ = 0. Using the formula:

0.15 m/s² = (v - 0)/[2 minutes*(60 s/1 min)]
Solving for v,
v = 18 m/s
3 0
3 years ago
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