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2 years ago

PLEASE HELP! I DONT KNOW WHAT TO DO! ITS ALOT PLEASE HELP THO!

Chemistry

1 answer:

kirza4 [7]2 years ago

7 0

Answer:

CuCl2 (aq) + (NH4)2CO3(aq) → NH4Cl(aq) + CuCO3(s)

* CuCl2 (aq) + (NH4)2CO3(aq) → 2NH4Cl(aq) + CuCO3(s)

*Cu(2+)(aq)+ 2Cl(-)(aq) + 2NH4(+)(aq) + CO3(2-)(aq) →2NH4(+)(aq) + Cl(-)(aq) + CuCO3(s)

*Cu(2+)(aq)+ CO3(2-)(aq) → CuCO3(s)

*2HCl(aq) + 2MgCO3(s) → 2MgCl(aq) + H2O(l) + 2CO2(g)

* 2H(+)(aq) + 2Cl(-)(aq) + 2MgCO3(s) → 2Mg(2+)(aq) +2Cl(-) (aq) + H2O(l) + 2CO2(g)

* 2MgCO3(s) → 2Mg(2+)(aq) + H2O(l) + 2CO2(g)

*ZnCl2(aq) + 2AgC2H3O2(aq) → 2AgCl(s) + Zn(C2H3O2)2(aq)

*Zn(2+)(aq) + 2Cl(-)(aq) + 2Ag(+)(aq) + C2H3O2(-)(aq) → 2AgCl(s) + Zn(2+)(aq) 2C2H3O2(-)(aq)

*2Cl(-)(aq) + 2Ag(+)(aq) → 2AgCl(s)

*MnO(s) + H2SO4(aq) → MnSO4(s) + H2O (l)

*MnO(s) + 2H(+)(aq) + SO4(2-)(aq) → MnSO4(s) + H2O (l)

*FeS(s) + 2HCl (aq) → FeCl2(aq) + H2S(g)

*FeS(s) + 2H(+)(aq) + 2Cl(-)(aq) → Fe(2+)(aq)+ 2Cl(-)(aq)) + H2S(g)

*FeS(s) + 2H(+)(aq) → Fe(2+)(aq)+ H2S(g)

Explanation:

In the first equation you only need to know the rules of solubility. All chlorides are solubles except Ag+ Pb+2 and Hg2(2+) and most carbonates are insolubles

For ionic equations Start with a balanced molecular equation. Break all soluble strong electrolytes (compounds with (aq) beside them) into their ions indicate the correct formula and charge of each ion . Indicate the correct number of each ion and write (aq) after each ion . Bring down all compounds with (s), (l), or (g) unchanged.

For net ionic equations Write the balanced molecular equation. Write the balanced complete ionic equation. Cross out the spectator ions that are present. Write the "leftovers" as the net ionic equation.

Before this, te equation must be balanced.

* CuCl2 (aq) + (NH4)2CO3(aq) → 2NH4Cl(aq) + CuCO3(s)

*Cu(2+)(aq)+ 2Cl(-)(aq) + 2NH4(+)(aq) + CO3(2-)(aq) →2NH4(+)(aq) + Cl(-)(aq) + CuCO3(s)

*Cu(2+)(aq)+ CO3(2-)(aq) → CuCO3(s)

*2HCl(aq) + 2MgCO3(s) → 2MgCl(aq) + H2O(l) + 2CO2(g)

* 2H(+)(aq) + 2Cl(-)(aq) + 2MgCO3(s) → 2Mg(2+)(aq) +2Cl(-) (aq) + H2O(l) + 2CO2(g)

* 2MgCO3(s) → 2Mg(2+)(aq) + H2O(l) + 2CO2(g)

*ZnCl2(aq) + 2AgC2H3O2(aq) → 2AgCl(s) + Zn(C2H3O2)2(aq)

*Zn(2+)(aq) + 2Cl(-)(aq) + 2Ag(+)(aq) + C2H3O2(-)(aq) → 2AgCl(s) + Zn(2+)(aq) 2C2H3O2(-)(aq)

*2Cl(-)(aq) + 2Ag(+)(aq) → 2AgCl(s)

*MnO(s) + H2SO4(aq) → MnSO4(s) + H2O (l)

*MnO(s) + 2H(+)(aq) + SO4(2-)(aq) → MnSO4(s) + H2O (l)

*FeS(s) + 2HCl (aq) → FeCl2(aq) + H2S(g)

*FeS(s) + 2H(+)(aq) + 2Cl(-)(aq) → Fe(2+)(aq)+ 2Cl(-)(aq)) + H2S(g)

*FeS(s) + 2H(+)(aq) → Fe(2+)(aq)+ H2S(g)

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A solution of hydrochloric acid of unknown concentration was titrated with 0.10 M NaOH. If a 100.-mL sample of the HCl solution

madam [21]

Answer: The initial pH of the HCl solution is 3

Explanation:

To calculate the concentration of acid, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is HCl

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is NaOH.

We are given:

$n_1=1\\M_1=?M\\V_1=100mL\\n_2=1\\M_2=0.10M\\V_2=1mL$

Putting values in above equation, we get:

$1\times M_1\times 100=1\times 0.10\times 1\\\\M_1=\frac{1\times 0.10\times 1}{1\times 100}=10M$

1 mole of HCl produces 1 mole of $H^+$ ions and 1 mole of $Cl^-$ ions

To calculate the pH of the solution, we use the equation:

$pH=-\log[H^+]$

We are given:

$[H^+]=0.001M$

Putting values in above equation, we get:

$pH=-\log (0.001)\\\\pH=3$

Hence, the initial pH of the HCl solution is 3

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2 years ago

Which of the following is more electronegative:

Firdavs [7]

The answer is 1) CF3
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but the equivalent of Hydrogen is +1 so it aims to give an electron. which means it's electropositive.

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2 years ago

Which of the following statements is true for an exothermic reaction?

shutvik [7]

The enthalpy change for an exothermic reaction is negative because heat is being released, so that takes out two of the responses. Since energy is being released into the surroundings due to the exothermic reaction, the potential energy of the products is lower than that of the reactants. Energy is being put in to make the reaction occur, but then that energy is all being released into the surroundings thus a lower potential energy level for the products

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2 years ago

Read 2 more answers

8. If I have 34 grams of FeO, how many grams of Oxygen were synthesized? Fe + O2 → Feo

krek1111 [17]

Answer:

34 gram of FeO produced 8 gram of oxygen.

Explanation:

Given data:

Mass of FeO = 34 g

Mass of oxygen = ?

Solution;

Chemical equation:

2FeO → 2Fe + O₂

Number of moles of FeO:

Number of moles = mass/ molar mass

Number of moles = 34 g /71.8 g/mol

Number of moles = 0.5 mol

Now we will compare the moles of FeO with oxygen:

FeO : O₂

2 : 1

0.5 : 1/2 × 0.5 = 0.25

Mass of oxygen:

Mass = number of moles × molar mass

Mass = 0.25 mol × 32 g/mol

Mass = 8 g

So 34 gram of FeO produced 8 gram of oxygen.

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2 years ago

1. look at the sequence of pictures what happened to the Apple overtime. 2. no chemical was added to the Apple explain why the A

Goshia [24]

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