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3 years ago

1) identify the physical state of the substances pictured.

Chemistry

1 answer:

Damm [24]3 years ago

3 0

Can't help because APPARENTLY there is a picture that goes along with the questions. Post it and I can help.

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Name the 3 largest countries in the Middle East

avanturin [10]

ANSWER:

1. Egypt

2. Turkey

3. Iran

Explanation:

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2 years ago

All of the following are strong acids except

IgorC [24]

Answer:

acetic acid

Explanation:

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2 years ago

Read 2 more answers

Does anyone know the answers for these

Alexeev081 [22]

Answer: 1. 0.045moles

2. 2.10 grams

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number $6.023\times 10^{23}$ of particles.

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}$

1. $\text{Number of moles of zinc nitrate}=\frac{8.51g}{189.36g/mol}=0.045moles$

2. Mass of $C_2H_4=moles\times {\text {Molar mass}}=0.075moles\times 28.05g/mol=2.10g$

4 0

2 years ago

On the Periodic Table, which elements are predominantly (mostly) gases with low densities?

aliya0001 [1]

I’m sorry if I wasted your time but I think it’s alkali metals but I’m
Not sure

5 0

2 years ago

Calculate the fractional saturation for hemoglobin when the partial pressure of oxygen is 40 mm Hg. Assume hemoglobin is 50%% sa

kumpel [21]

Answer:

The fractional saturation for hemoglobin is 0.86

Explanation:

The fractional saturation for hemoglobin can be calculated using the formula

$Y_{O_{2} } = \frac{(P_{O_{2} })^{h} } {(P_{50})^{h} + (P_{O_{2} })^{h} }$

Where $Y_{O_{2} } \\$ is the fractional oxygen saturation

${P_{O_{2} }$ is the partial pressure of oxygen

$P_{50}$ is the partial pressure when 50% hemoglobin is saturated with oxygen

and h is the Hill coefficient

From the question,

${P_{O_{2} }$ = 40 mm Hg

$P_{50}$ = 22 mm Hg

h = 3

Putting these values into the equation, we get

$Y_{O_{2} } = \frac{(P_{O_{2} })^{h} } {(P_{50})^{h} + (P_{O_{2} })^{h} }$

$Y_{O_{2} } = \frac{40^{3} }{22^{3} + 40^{3} }$

$Y_{O_{2} } = \frac{64000 }{10648 + 64000 }$

$Y_{O_{2} } = \frac{64000 }{74648 }$

$Y_{O_{2} } = 0.86$

Hence, the fractional saturation for hemoglobin is 0.86.

4 0

3 years ago