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3 years ago

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Find two consecutive even integers such that 3 times the smaller integer is 16 more than twice the larger

1 answer:

Verdich [7]3 years ago

4 0

n, n + 2 - two consecutive even integers

3n = 2(n + 2) + 16 |use distributive property

3n = (2)(n) + (2)(2) + 16

3n = 2n + 4 + 16

3n = 2n + 20 |subtract 2n from both sides

n = 20

n + 2 = 20 + 2 = 22

Answer: 20, 22.

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Please answer this question now

Alexeev081 [22]

Answer:

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Step-by-step Explanation:

Given:

∆UVW,

m < U = 33°

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Required:

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Solution:

Find side length UV using Law of Sines

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Cross multiply

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