Find two consecutive even integers such that 3 times the smaller integer is 16 more than twice the larger
1 answer:
n, n + 2 - two consecutive even integers
3n = 2(n + 2) + 16 |use distributive property
3n = (2)(n) + (2)(2) + 16
3n = 2n + 4 + 16
3n = 2n + 20 |subtract 2n from both sides
n = 20
n + 2 = 20 + 2 = 22
Answer: 20, 22.
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