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romanna [79]
3 years ago
12

In the design shown below, four semicircles are attached to a square whose area is 36 square centimeters. Which of the following

is closest to the total area of the shaded semicircles, measured in square centimeters?
Mathematics
1 answer:
CaHeK987 [17]3 years ago
3 0

Answer:

56.549 cm   (choice 1)

Step-by-step explanation:

If the area of the square if 36 cm, then each side is 6 cm.

That means the diameter for each semi circle is also 6 cm.

Formula for a semi circle is 1/2(πr²)

We need the radius, which is half the diameter. So the radius is 6÷2= 3

Now plug in to the formula.

A= 1/2(π3²)

A= 14.137 (nearest hundredths)

Now multiply that by 4, because there are 4 semi circles

4(14.137)= 56.549 cm (nearest hundredths)

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juin [17]

Answer:

  GI or HJ

Step-by-step explanation:

Diagonals connect non-adjacent vertices.

That is, the diagonal with G as an endpoint will not connect to vertices H or J, but will connect to vertex I. Likewise the diagonal with H as one end will have J as the other end. A quadrilateral has only two (2) diagonals. Of course, each can be named two ways:

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6 0
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How do I solve this problem
CaHeK987 [17]
Use cymath it gives you the answer :)
6 0
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In AABC, MZA = 16°, mZB = 49°, and<br> a = 4. Find c to the nearest tenth.
zhannawk [14.2K]

Answer:

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Step-by-step explanation:

The sum of angles in a triangle is 180°, so angle C is ...

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The measure of side c can be found from the Law of Sines:

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  c = a·sin(C)/sin(A) = 4·sin(115°)/sin(16°)

  c ≈ 13.2

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The population of Groverdale is
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