The six trigonometric ratios are sine (sin), cosine (cos), tangent (tan), cotangent (cot), cosecant (cosec), and secant (sec). In geometry, trigonometry is a branch of mathematics that deals with the sides and angles of a right-angled triangle. Therefore, trig ratios are evaluated with respect to sides and angles.

The given question can be solved by sin, as value of perpendicular is to be evaluated and height and angle is provided. Let height from the ground be x

sin(22.5°) = x / 58

x = 58sin22.5 = 58(.38258) = 22.5 feet high.

Thus the Boy is 22.5 feet high from the ground.

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6 0

1 year ago

Which expression is equivalent to Left-bracket log 9 + one-half log x + log (x cubed + 4) Right-bracket minus log 6? log StartFr

dybincka [34]

Answer:

$\log{\dfrac{3\sqrt{x}(x^3+4)}{2}}$

Step-by-step explanation:

$\log{9}+\dfrac{1}{2}\log{x}+\log{(x^3+4)}-\log{6}=\log{\left(\dfrac{9x^{\frac{1}{2}}(x^3+4)}{6}\right)}\\\\=\boxed{\log{\dfrac{3\sqrt{x}(x^3+4)}{2}}}\qquad\text{matches choice A}$

The applicable rules of logarithms are ...

log(ab) = log(a) +log(b)

log(a/b) = log(a) -log(b)

log(a^b) = b·log(a)

3 0

3 years ago