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3 years ago

If a solution of potassium hydroxide is mixed with sulfuric acid, which type of reaction will most likely occur?

2 answers:

7 0

If a solution of potassium hydroxide is mixed and or chemically reacted with sulphuric acid, the type of reaction that will occur is a Neutralization reaction or a unique type of a Double Replacement Reaction.

Solution = Double Replacement.

k0ka [10]3 years ago

3 0

I think the correct answer from the choices listed above is the last option. If a solution of potassium hydroxide is mixed with sulfuric acid, the type of reaction that will most likely occur would be a double replacement. The reaction is written as:

KOH + H2SO4 = K2SO4 + H2O

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Which of the following characteristics helps to distinguish a biome?

ladessa [460]

Answer: a biome is defined by its biogeography, temperature, and precipitation

Explanation:

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3 years ago

What would you need to do to calculate the molality of 10 g of NaCl in 2 kg of

jasenka [17]

Answer:

O B. Convert the 10 g of NaCl to moles of NaCl.

Explanation:

The formula for finding the molality is m=moles of solute/kg of solvent. The solute for this question is NaCl and the solvent is water.

(10g NaCl)(1 mol NaCl/58.44g NaCl)=0.1711 mol NaCl

58.44 is the molar mass of NaCl

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3 years ago

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3 years ago

What is the percent by mass of oxygen?

Colt1911 [192]

Answer:

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Explanation:

3 0

3 years ago

Consider the balanced reaction: 4Ga(s) + 3O2(g)⟶ 2Ga2O3(s)

Paha777 [63]

First we need to find the number of moles that 43.9g of gallium metal is. We can do this by finding the molar weight of gallium and cross-multiplying to cancel out units:

$\frac{1mole}{69.723g}*\frac{43.9g}{1}=0.63mol_{Ga}$

So we are dealing with 0.63 moles of gallium metal.

We can take from the balanced equation that 4 moles of gallium metal will react completely with 3 moles of oxygen gas. We can take this ratio and make a proportion to find the amount of oxygen gas, in moles, that will react completely with 0.63 moles of gallium metal:

$\frac{4moles_{Ga}}{3moles_{O_{2}}} =\frac{0.63moles_{Ga}}{xmoles_{O_{2}}}$

Cross multiply and solve for x:

$4x=1.89$

$x=0.47moles_{O{2}}$

So now we know that 0.47 moles of oxygen gas will react with 43.9g of gallium metal.

5 0

3 years ago