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LiRa [457]
3 years ago
5

Plz help asap 3 problums i will give brailyest

Physics
1 answer:
Bumek [7]3 years ago
3 0

Answer:

the answer is 104568948 degress

Explanation:

yeeeeeee

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The amount of matter in an object is mass or weight
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In wet climates, granite weathers more slowly than ____
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Explorers on a small airless planet used a spring gun to launch a ball bearing vertically upward from the surface at a launch ve
Oksana_A [137]

Answer:

gs = 0.6 m/s^2

Explanation:

Given data:

velocity = 12 m/s

height s = 12t -(1/2) g_s t^2

Given velocity is the derivatives of  height

v(t) = \frac{d}{dt} s(t)

      = \frac{d}{dt}(12t -\frac{1}{2} g_s t^2)

      = 12 - g_s t

when velocity tend to 0 , maximum height is reached

v(t) = 12 - g_s t

0 = 12 - g_s t

g_s = \frac{12}{t}

at t = 20 sec ball reached the max height, so

g_s = \frac{12}{20} = 0.6 m/s^2

5 0
3 years ago
You need to use your cell phone, which broadcasts an 830 MHz signal, but you’re in an alley between two massive, radio- wave-abs
Korvikt [17]

Answer:Angular width of the electromagnetic wave after it emerges from between the buildings is 2.761 degree

Explanation:

The wavelength of the electromagnetic wave is

\lambda=\frac{c}{f} \\\lambda=\frac{3\times 10^8}{830\times 10^6} \\\lambda=0.361 m

Consider two buildings as a single slit, for single slit diffraction dark fringes are located an angle of

\theta _{p}=sin^{-1}\frac{\lambda}{a}

where \lambda is frequency, a is space between buildings.

For the first dark fringes

\theta _{1}=sin^{-1}\frac{\lambda}{a}\\\theta _{1}=sin^{-1}\frac{0.3614}{15}\\\theta _{1}=1.38^{0}

Angular width of the electromagnetic wave after it emerges from between the buildings is

\Delta\theta =2\theta _{1}\\\Delta\theta =2\times 1.38\\\Delta\theta =2.761^0

6 0
3 years ago
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