The range (maximum horizontal distance) travelled by a projectile is given by the formula
R = V^2(sin 2A)/g
where
R = range
V = initial velocity of ball = 64 ft/sec. (given)
A = angle of launch = 45 degrees (given)
g = acceleration due to gravity = 32.2 ft/sec^2 (constant)
Substituting values,
R = 64^2(sin 2*45)/9.8
R = 127.20 feet
Since the receiver is 60 yards away (180 feet), he will have to travel a distance of 180 - 127.20 = 52.80 feet to catch the ball.
The ball's total travel time is given by the formula
T = 2V(sin A)/g
where all the terms have been previously defined.
Substituting values,
T = 2(64)(sin 45)/32.2
T = 2.82 sec.
Therefore, in order for the receiver to catch the ball, his speed must be equal to
52.80/2.82 = 18.72 ft/sec.
Hope this helps ya
Answer:
The average velocity is
and 
respectively.
Explanation:
Let's start writing the vertical position equation :
Where distance is measured in meters and time in seconds.
The average velocity is equal to the position variation divided by the time variation.
= Δx / Δt = 
For the first time interval :
t1 = 5 s → t2 = 8 s
The time variation is :
For the position variation we use the vertical position equation :
Δx = x2 - x1 = 1049 m - 251 m = 798 m
The average velocity for this interval is
For the second time interval :
t1 = 4 s → t2 = 9 s
Δx = x2 - x1 = 1495 m - 125 m = 1370 m
And the time variation is t2 - t1 = 9 s - 4 s = 5 s
The average velocity for this interval is :
Finally for the third time interval :
t1 = 1 s → t2 = 7 s
The time variation is t2 - t1 = 7 s - 1 s = 6 s
Then
The position variation is x2 - x1 = 701 m - (-1 m) = 702 m
The average velocity is
I think the correct answer is hydrolysis. The name <span>of the process that puts adenosine diphosphate (ADP) and phosphate (P) together to reform ATP is called hydrolysis. Hope this answers the question. Have a nice day. Feel free to ask more questions.</span>
